Physics NCERT Exemplar Solutions Class 12th Chapter Twelve

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P
Payal Gupta

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U = 3PV + 4

nCvT=3PV+4

n*fRT2=3PV+4

f=6+8PV

f>6polyatomic

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A
alok kumar singh

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 Electric field due to infinite sheet is uniform.

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alok kumar singh

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Kindly go through the solution 

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alok kumar singh

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Mono atomic ? Cv=3R2Cp=5R2

Di- atomic ? CV=5R2Cp=7R2

(Rigid)

Di-atomic ? Cv=7R2Cp=9R2

(Non-Rigid)

Tri-atomic ? CV=3RCP=4R

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alok kumar singh

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Uinitial =k (4q) (q) (d/2)+k (q) (-q) (d/2)

6kq2dUfinal =4 (4q) (q)3d2+k (q) (-q) (d/2)23kq2dΔU=23-6kq2d-163kq2d

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alok kumar singh

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Kindly go through the solution 

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alok kumar singh

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V 2 = U 2 + 2 g S V 2 = 0 + 2 g ( h - y ) V 2 = 2 g h - 2 g y V = 2 g h - 2 g y

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alok kumar singh

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 1λmin =R11-1=R[n=n=1]

1λmax=R11-14=3R4[n=2n=1]

Δλ43R-1R13R=340

For Paschan 1λmin =R19[n=h=3]

1λmax=R19-116=7R144

Δλ=817R

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alok kumar singh

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n1T1+n2T2=nT

(0.1) (200)+ (0.05) (400)= (0.15)T

T=266.67

6.25

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alok kumar singh

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(n) λ=5

(n, m) : Integers

2m+12λ=323/25=2m+12n3n=10m+5

N, m are integers.

So,  m=1, n=5, λ=1

m=4n=15λ=13m=7n=25λ=15

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