Physics Nuclei

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New answer posted

3 weeks ago

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V
Vishal Baghel

Contributor-Level 10

Energy of products = 939 + 940 = 1879
ΔE + E_reactions – E_productor = 1877 – 1879 = -2MeV.
Hence it must capture a γ - ray photon of energy 2MeV.

New answer posted

3 weeks ago

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R
Raj Pandey

Contributor-Level 9

7 14 N contains 7 protons and 7 neutrons.

Mass defect,   Δ m = 7 m H + 7 m n - m 14 7 = ( 7 * 1.00783 u ) + ( 7 * 1.00867 u ) - 14.00307 u

= 0.11243 u

Binding energy = 0.11243 * 931.5 M e V = 104.7 M e V

New answer posted

3 weeks ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

t? , half life = (log?2)/λ = 3 s
Initially 200 nuclei were there
After 3 half-lives, 9 seconds,
No. of nuclei = (1/2³) (200) = 25
Therefore, the number of nuclei that decayed = 200 – 25 = 175

New answer posted

4 weeks ago

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V
Vishal Baghel

Contributor-Level 10

N = [n + n/10 + n/100 + .]
= n/ (1 - 1/10) = 10/9

New answer posted

4 weeks ago

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R
Raj Pandey

Contributor-Level 9

N N 0 = 1 16 = 1 2 t T 1 / 2

t = 4 T 1 / 2 = 20 * 4 = 80   minutes  

New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image 

 

 

New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

R = R 0 ( A ) 1 / 3 R 1 R 2 = 125 64 1 / 3 = 5 4

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a month ago

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New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

A A 0 = 1 2 t / T H = 1 2 150 / 100 = 1 2 2

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

Z A X β + Z - 1 B α Z - 3 β - Z - 2 D

β + decreases atomic number by 1

α decreases atomic number by 2

β - increases atomic number by 1

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