Physics Nuclei

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New answer posted•a year ago

Physics Nuclei Nuclei

A liquid of density 750 kgm^-3 flows smoothly through a horizontal pipe that tapers in cross-sectional area from A₁ = 1.2 × 10^-2m² to A₂ = $\frac{A_{1}}{2} .$ The pressure difference between the wide and narrow sections of the pipe is 4500 Pa. The rate of flow of liquid is_________ × 10^-3m³s^-1.

8 Views|Posted a year ago

Asked by Alok Kumar Singh

Answered by

Alok Kumar Singh | Contributor-Level 10

a year ago

Given A₂ = $\frac{_{}}{}$ $\frac{A_{1}}{2}$

Bernoulli’s b/w (1) & (2)

$\frac{P_{1}}{ρ g} + \frac{v_{1}^{2}}{2 g} + z_{1} = \frac{ρ_{2}}{ρ g} + \frac{v_{2}^{2}}{2 g} + z_{2}$

[z₁= z₂]

$\frac{P_{1} - P_{2}}{ρ g} = \frac{v_{2}^{2} - v_{1}^{2}}{2 g}$

[Q = A₁V₁ = A₂V₂]

$\frac{4500}{750} = \frac{{(\frac{Q}{A_{2}})}^{2}}{2} - {(\frac{Q}{A_{1}})}^{2}$

$12 = Q^{2} [\frac{1}{A_{2}^{2}} - \frac{1}{A_{1}^{2}}]$

$Q = 2 A_{1} = 2 \times 1.2 \times 1 0^{- 2}$

= 2.4 × 10^-2 m³ /sec

= 24 × 10^-3 m³ /sec

= 24

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New answer posted•a year ago

Physics Nuclei Class 12th

Following statements related to radioactivity are given below:

(A) Radioactivity is a random and spontaneous process and is dependent on physical and chemical conditions.

(B) The number of un-decayed nuclei in the radioactive sample decays exponentially with time.

(C) Slope of the graph of log_e (no. of undecayed nuclei) Vs, time represents the reciprocal of mean life time $(τ) .$

(D) Product of decay constant $(λ)$ and half-life time $(T_{1 / 2})$ is not constant.

5 Views|Posted a year ago

Asked by Alok Kumar Singh

Answered by

Alok Kumar Singh | Contributor-Level 10

a year ago

We know, N = $N_{0} e^{- λ t}$

Where, N Number of un-decayed Nuclei

No Initial No. Of Nuclei

N $e^{- λ t}$

$N = N_{0} {\bar{e}}^{λ t}$

Taking log both side log N = log N0 + loge $e^{- λ t}$

log N = log No $λ t$

Slope = $λ = \frac{1}{t_{a v}}$

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New answer posted•a year ago

Physics Nuclei Class 12th

$\sqrt[]{d_{1}} a n d \sqrt[]{d_{2}}$ are the impact parameters corresponding to scattering angles 60° and 90° respectively, when an a particle is approaching a gold nucleus. For d₁ = x d₂, the value of x will be________.

3 Views|Posted a year ago

Asked by Alok Kumar Singh

Answered by

Alok Kumar Singh | Contributor-Level 10

a year ago

$\sqrt[]{d}$ $c o t \frac{θ}{2}$

cot² 30° = x cot² 45°

x = 3

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New answer posted•a year ago

Physics Nuclei Physics NCERT Exemplar Solutions Class 12th Chapter Thirteen

The activity of a radioactive material is 2.56 × 10^-³ Ci. If the half life of the material is 5 days, after how many days the activity will become 2 × 10^-⁵ Ci?

4 Views|Posted a year ago

Asked by Alok Kumar Singh

Answered by

Alok Kumar Singh | Contributor-Level 10

a year ago

A₀ = 2.56 × 10^-3C_i

A = 2 × 10^-15C_i

A = ^{$\frac{A_{0}}{2^{n}}$}

$\Rightarrow 2 \times 1 0^{- 5} = \frac{2.56 \times 1 0^{- 3}}{2^{n}}$

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New answer posted•a year ago

Physics Nuclei Physics NCERT Exemplar Solutions Class 12th Chapter Thirteen

Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below: ${}_{1}^{2}X +_{1}^{2} X = \frac{4}{2} Y$

The binding energies per nucleon for are 1.1 Me V and 7.6

Me V respectively. The energy released in this process is________ Me V.

7 Views|Posted a year ago

Asked by Alok Kumar Singh

Answered by

Alok Kumar Singh | Contributor-Level 10

a year ago

Energy released = Binding energy of product – Binding energy of reacts :

$Δ E = 7.6 \times 4 - (1.1 \times 4)$

= 26 MeV

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A liquid of density 750 kgm-3 flows smoothly through a horizontal pipe that tapers in cross-sectional area from A1 = 1.2 × 10-2m2 to A2 = A 1 2 . The pressure difference between the wide and narrow sections of the pipe is 4500 Pa. The rate of flow of liquid is_________ × 10-3m3s-1.

d 1 a n d d 2 are the impact parameters corresponding to scattering angles 60° and 90° respectively, when an a particle is approaching a gold nucleus. For d1 = x d2, the value of x will be________.

The activity of a radioactive material is 2.56 × 10-3 Ci. If the half life of the material is 5 days, after how many days the activity will become 2 × 10-5 Ci?

Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below: X12+12X=42Y The binding energies per nucleon for are 1.1 Me V and 7.6 Me V respectively. The energy released in this process is________ Me V.

$\sqrt[]{d_{1}} a n d \sqrt[]{d_{2}}$ are the impact parameters corresponding to scattering angles 60° and 90° respectively, when an a particle is approaching a gold nucleus. For d₁ = x d₂, the value of x will be________.

The activity of a radioactive material is 2.56 × 10^-³ Ci. If the half life of the material is 5 days, after how many days the activity will become 2 × 10^-⁵ Ci?

Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below: ${}_{1}^{2}X +_{1}^{2} X = \frac{4}{2} Y$

The binding energies per nucleon for are 1.1 Me V and 7.6

Me V respectively. The energy released in this process is________ Me V.