Physics Nuclei
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2 months agoNew answer posted
2 months agoContributor-Level 10
decreases atomic number by 1
decreases atomic number by 2
increases atomic number by 1
New answer posted
2 months agoContributor-Level 9
From Radioactive Decay Law,
dN/dt = λ? N + λ? N = λ_eff N
⇒ λ_eff = λ? + λ? ⇒ ln (2)/T = ln (2)/T? + ln (2)/T? ⇒ T = (T? ) / (T? + T? )
(where T, T? , and T? are half-lives)
New answer posted
2 months agoContributor-Level 10
Total mass of reactant should be greater than that of product.
This condition is only fulfilled in case- 3
New answer posted
2 months agoContributor-Level 10
The law of radioactive decay is N = N? e? λt, where N is the amount remaining at time t.
Given that at time t, N/N? = 9/16.
So, 9/16 = e? λt
At time t/2, the fraction remaining will be N'/N?
N' = N? e? λ ( t/2 ) = N? (e? λt)¹/²
Substituting the value of e? λt:
N' = N? (9/16)¹/² = N? (3/4)
The fraction remaining is N'/N? = 3/4.
New answer posted
2 months agoContributor-Level 10
P = E/t
= 2/235 * (6.023*10²? *200*1.6*10? ¹? )/ (30*24*60*60) = 60W
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