Physics Nuclei
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New question posted
3 months agoNew answer posted
3 months agoContributor-Level 10
A = Activity = λN = (ln (2)/t? /? ) N
N = (1.5*10? ³ / 198) * 6*10²³
A = (0.693 / (2.7*24*3600) * (1.5*10? ³ / 198) * 6*10²³ disintegration/s
A ≈ 1.32 * 10¹³ Bq = (1.32*10¹³ / 3.7*10¹? ) Ci ≈ 357 Ci
New answer posted
3 months agoContributor-Level 10
N? /N? = e?
For 33% decay, N? /N? = 0.67 ≈ 2/3.
2/3 = e? ⇒ t? = (1/λ)ln (3/2)
For 67% decay, N? /N? = 0.33 ≈ 1/3.
1/3 = e? ⇒ t? = (1/λ)ln (3)
Δt = t? - t? = (1/λ) [ln (3) - ln (3/2)] = (1/λ)ln (2) = T? /? = 20 min
New answer posted
3 months agoContributor-Level 10
A = A? (1/2)?
A/A? = 1/8 = (1/2)³ ⇒ n = 3
t = n T½
30 = 3 T½
T½ = 10 years
New answer posted
3 months agoContributor-Level 9
t? /? = 3 days = 72 hours
dN/dt = λN = (ln2/t? /? ) N
= (0.693 * 6.02*10²³ * 2*10? ³) / (72 * 3600 * 198)
= 1.618 * 10¹³
= 16.18 * 10¹² disintegration/second
New answer posted
3 months agoContributor-Level 10
Binding Energy = (Δm)c²
= [Zmp + (A-Z)mn - MAl]c²
= [ (13*1.00726 + 14*1.00866) - 27.18846] u
= [ (13.09438 + 14.12124) - 27.18846] u
= [27.21562 - 27.18846] u
= 0.02716 u
= 0.02716 x = 27.16x * 10? ³
New answer posted
3 months agoContributor-Level 9
3N? /4 = N? e?
⇒ e? = 4/3
t? = (1/λ) ln (4/3)
t? = ln2/λ
t? - t? = (1/λ)ln2 - (1/λ)ln (4/3)
= (1/λ)ln (2/ (4/3) = (1/λ)ln (3/2)
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