Physics Nuclei

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New answer posted

5 days ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

a week ago

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A
alok kumar singh

Contributor-Level 10

Q = [4 *4.0026 – 15.9994] *931.5 MeV

Q = 10.2 MeV

New answer posted

a week ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

 

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a week ago

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A
alok kumar singh

Contributor-Level 10

N N0eλt

->t = λN = N0/e

So number of nuclei decayed = N0N

N0 (1- 1/e) 

New answer posted

2 weeks ago

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A
alok kumar singh

Contributor-Level 10

Density of nuclei is order of 1017 kg m–3.

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution '

 

New answer posted

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R
Raj Pandey

Contributor-Level 9

Two successive β decays increase the charge no. by 2.

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A
alok kumar singh

Contributor-Level 10

X + H 1 1 H e 2 4 + O 8 16 Z A

Z + 1 = 2 + 8 ? Z = 9 X F

A + 1 = 4 + 16 A = 19

X Z A = F 9 19

N 7 14 + Y Z A H 1 1 + C 6 14

7 + Z = 1 + 6 ? Z = 0

14 + A = 1 + 14 ? A = 1

? Y Z A = n 0 1

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2 weeks ago

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V
Vishal Baghel

Contributor-Level 10

Density of nuclei is order of 1017 kg m-3.

New answer posted

2 weeks ago

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V
Vishal Baghel

Contributor-Level 10

t = T 2 N = N 0 ( 1 2 ) t T

N = N 0 ( 1 2 ) 1 2 = N 0 2

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