Physics Ray Optics and Optical Instruments

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New answer posted

4 weeks ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

1 2 0 = ( 1 . 5 1 ) ( 2 R )

R = 20cm

1 f ' = ( 1 . 5 1 . 6 1 ) ( 2 R )            

= 1 1 6 * 2 2 0                  

f' = – 160cm

New answer posted

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

| m | = | v u | = 2  

|v| = |2u|

n + 2n = 45

n = 15 cm

u = –15

v = 30

1 v + 1 u = 1 f  

1 3 0 + 1 1 5 = 1 f  

1 2 3 0 = 1 3 0 = 1 f  

f = 30 cm

New answer posted

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

  1 f = ( μ 1 ) ( 2 R )                    f = 20 cm

1 v 1 u = 1 f

1 v + 1 1 0 = 1 2 0

             

             

New answer posted

a month ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

For normal emergence

r = A

From Snell's Law

sin ? i sin ? r = μ 1

? sin ? i = 2 sin ? 30 0

? i = 45 0

New answer posted

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Magnify power of telescope for far point is given as

m = θ i θ 0 = f 0 f e

? θ i = θ 0 f 0 f e = 1 0 100 5 = 20 0

New answer posted

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

For thin prism, deviation  = μ - 1 A

New answer posted

a month ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

From figure, Sin  sin C=3(4)2+(3)2=35

where C is the critical angle.

Also,  sin C=lμa

Sin  sin C=1aμl   [ Since l μ a = 1 a μ l ]

Also a μ l = v e l o c i t y o f l i g h t i n a i r ( c ) v e l o c i t y o f l i g h t i n l i q u i d ( ν ) ... Sin  sin C=vc=v3*108

or v = 3 * 1 0 8 * 3 5 = 1 . 8 * 1 0 8 m s 1

New answer posted

a month ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

Please consider the following Image

 

New answer posted

a month ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

Please find the answer below

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