Physics Ray Optics and Optical Instruments

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New answer posted

4 months ago

0 Follower 4 Views

J
Jaya Sharma

Contributor-Level 10

Yes, optical instruments are used in modern medicine for many purposes including surgery, monitoring, research and diagnosis. Let us take a look at each one by one:

  • Many optical instruments are used for visualizing internal structures for diagnosis of a disease and its monitoring. These include Ophthalmoscope, Endoscope, Colposcope and Dermatoscope. 
  • Optical instruments are also used for precision and minimally invasive surgeries, including Laparoscope, Arthroscope and Surgical Microscopes.
  • Lasers are used for cutting, therapy and coagulation since they have precision and minimal invasiveness. CO? Laser, Excimer Laser and Fiber Optic
...more

New answer posted

4 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

d = f 1 - f 2
= 20 - 5
= 15 c m
(1)
q = C V
d q d t = C d V d t
I d = C V 0 ω c o s ? ω t
= V 0 ω C o s ω t

New answer posted

4 months ago

0 Follower 10 Views

R
Raj Pandey

Contributor-Level 9

Common potential V C = C 1 V 1 + C 2 V 2 C 1 + C 2 = C * 100 + C * 0 C + C = 50   Volt  

Electrostatic energy stored = 2 * 1 2 C V 2 = C V 2 = 2.25 * 10 - 6 J

New answer posted

4 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

P = 1 f = ( μ - 1 ) 1 R 1 - 1 R 2

P = 3 2 - 1 1 0.2 + 1 0.2

P = 1 2 2 0.2 = 10 2 = + 5 D

New answer posted

4 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

Because angle of incidence is Brewster's angle so that angle between reflected and refracted ray is 90 ?

t a n ? i p = μ = 3

i p = 60 ? = i

New answer posted

4 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

N N 0 = 1 16 = 1 2 t T 1 / 2

t = 4 T 1 / 2 = 20 * 4 = 80   minutes  

New answer posted

4 months ago

0 Follower 3 Views

J
Jaya Sharma

Contributor-Level 10

You can identify whether a medium has higher or lower refractive index through the three ways. The first step is to observe the direction of bending. In this case, if the light is bending towards the normal, the second medium has higher refractive index. If the light bends away from normal, first medium has higher index of refraction. 

In the second method, you can use Snell's law. If the second angle is smaller than the first one, second medium has higher refractive index. In case the first angle is smaller than second one, first medium has higher index of refraction. The third method is critical angle method where, if the light u

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New answer posted

4 months ago

0 Follower 3 Views

J
Jaya Sharma

Contributor-Level 10

When these two media are compared, then, it is evident that rarer medium has lower refracted index as compared to denser medium. Denser media like glass and water have higher refractive index whereas rarer medium like air and vacuum have lower refractive index. Due to this, the light will bend towards the normal when it travels from rarer to denser medium. On the other hand, light will bend away from normal when it travels from denser to a rarer medium.

New answer posted

4 months ago

0 Follower 5 Views

J
Jaya Sharma

Contributor-Level 10

Whenever a light ray travels from a rarer medium to a denser medium through a spherical surface, relationship between object distance (u), image distance (v), radius of curvature (R) and refractive index ( n 1 and n 2 ) is given by refraction formula for spherical surfaces as follows.

n 2 v - n 1 u = n 2 - n 1 R

 

  • n 1 is the refractive index of medium that contains the object (on the left side)
  • n 2 is refractive index of medium that will contain the image (on the right side)

New answer posted

5 months ago

0 Follower 5 Views

J
Jaya Sharma

Contributor-Level 10

Yes, total internal reflection can occur in both sound and water waves, including light waves, since it follows the same principle. Whenever a light/sound/water wave travels from denser to rarer medium and strikes the boundary of the medium at an angle greater than critical angle, the wave entirely reflects back into denser medium rather than refracting. Sonar waves in submarine reflect back entirely from the water surface as it hits at a steep angle. In water, ocean waves approach beach and slow down because of shallower water. If a wave hits the boundary of deep and shallow water at a steep angle, these waves will reflect back toward

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