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Physics Ray Optics and Optical Instruments

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4 months ago

Physics Ray Optics and Optical Instruments Class 12th

The refracting angle of a prims is A and refractive index of the material of the prism is cot (A/2). Then the angle of minimum deviation will be-

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Raj Pandey

Contributor-Level 9

At minimum deviation –

$δ = 2 i - A \Rightarrow i = \frac{δ + A}{2}, r = \frac{A}{2}$

Using snell's low : - $s i n i = μ = s i n r$

$\Rightarrow \frac{δ + A}{2} = \frac{π - A}{2} \Rightarrow δ = π - 2 A$

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4 months ago

Physics Ray Optics and Optical Instruments Class 12th

The speed of light in media 'A' and 'B' are 2.0 * 10¹⁰ cm/s and 1.5 * 10¹⁰ cm/s respectively. A ray of light enters from the medium B to an incident angle 'q'. If the ray suffers total internal reflection, then

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alok kumar singh

Contributor-Level 10

$\frac{s i n θ_{C}}{V_{B}} = \frac{s i n 90 °}{V_{A}} \Rightarrow s i n θ_{C} = \frac{V_{B}}{V_{A}} = \frac{1.5 * 1 0^{10}}{2.0 * 1 0^{10}} = \frac{3}{4}$

According to question, we can write

$θ > θ = s i n^{- 1} (\frac{3}{4})$

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4 months ago

Physics Ray Optics and Optical Instruments Class 12th

A circular coil of 1000 turns each with area 1m² is rotated about its vertical diameter at the rate of one revolution per second in a uniform horizontal magnetic field of 0.07 T. The maximum voltage generation will be ________V.

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alok kumar singh

Contributor-Level 10

given N = 1000 turns

A = 1m²

$ω = 1 r e v / s e c$

$= 1 * 2 π r a d / s e c$

$V = \frac{- d ?_{B}}{d t} = \frac{- d}{d t} (N B A c o s ω t)$

= $140 * \frac{22}{7}$

= 20 * 22

= 440 volts

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4 months ago

Physics Ray Optics and Optical Instruments Class 12th

Two identical thin biconvex lenses of focal length 15 cm and refractive index 1.5 are in contact with each other. The space between the lenses is filled with a liquid of refractive index 1.25. The focal length of the combination is ________ cm.

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alok kumar singh

Contributor-Level 10

f₁ = 15 cm

$P_{1} = \frac{1}{15} * 100 = \frac{100}{15} D$

$P_{3} = \frac{100}{15} D$

$\frac{1}{f^{2}} = (μ_{2} - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}})$

$= (1.25 - 1) * \frac{- 2}{R}$

$\frac{1}{f_{2}} = \frac{0.25 * - 2}{15}$

$\frac{1}{f_{2}} = \frac{- 1}{30} c m^{- 1}$

$\begin{array}{l} p_{2} = \frac{1}{f_{2}} = - \frac{100}{30} \\ P_{R} = P_{1} + P_{2} + P_{3} \\ P_{R} = \frac{100}{15} - \frac{100}{30} + \frac{100}{15} \\ P_{R} = 10 D \end{array}$

$P_{R} = \frac{1}{f_{R}}$

$f_{R} = \frac{1}{10} * 100 c m$

$f_{R} = 10 c m$

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4 months ago

Physics Ray Optics and Optical Instruments Class 12th

You are given a converging lens with equal radii of curvature and a diverging lens with the same radii of curvature as those of the converging lens. The lenses are made of material with n = 1.50, the radii of curvature are all 35cm. They are placed at opposite ends of a tube 15cm long, and the nearer lens which is converging is 10cm from an object. What is the location of the image that results from the two refractions? Write the final distance (in cm) from diverging lens.

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Vishal Baghel

Contributor-Level 10

$\frac{1}{u} + \frac{1}{- 10} = \frac{1}{35}$

$\begin{array}{l} \frac{1}{u} = \frac{1}{35} - \frac{1}{10} = \frac{2 - 7}{70} = \frac{- 1}{14} \\ \frac{1}{u} = \frac{- 1}{35} - \frac{1}{29} = \frac{- 64}{35 * 29} \\ u = \frac{35 * 29}{64} = 15.85 t o 15.86 \end{array}$

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4 months ago

Physics Ray Optics and Optical Instruments Class 12th

You are trying to construct a compound microscope given two lenses with focal lengths f₁ = 1.0cm and f₂ = 4.0cm. How far apart (in cm) should you place the lenses in order to obtain an angular magnification of 60? (Assume normal adjustment of microscope)

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Vishal Baghel

Contributor-Level 10

For better resolution, smaller focal length should be objective.

h0 = 1 cm fe = 4cm.

$\begin{array}{l} Q_{0} = \frac{h_{0}}{25} \\ Q = \frac{60 h_{0}}{25} = \frac{h_{I}}{4} \end{array}$

$\frac{L - 5}{1} = \frac{h_{I}}{h_{0}} = \frac{240}{25}$

L = 14.6 cm

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4 months ago

Physics Ray Optics and Optical Instruments Class 12th

A lens is placed between a source of light and screen. It forms real image on screen for two different positions. If height of one image is 20 cm and the other is 80 cm, then the height of source of light (in cm) is_____.

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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New answer posted

4 months ago

Physics Ray Optics and Optical Instruments Class 12th

Car B overtakes another car A at a relative speed of 40ms^-¹. How fast will the image of car B appear to move in the mirror of focal length 10cm fitted in car A, when the car B is 1.9m away from the car A?

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

For mirror

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4 months ago

Physics Ray Optics and Optical Instruments Class 12th

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New answer posted

4 months ago

Physics Ray Optics and Optical Instruments Class 12th

A glass tumbler having inner depth of 17.5cm is kept on a table. A student starts pouring water $(μ = 4 / 3)$ into it while looking at the surface of water from the above. When he feels that the tumbler is half filled, he stops pouring water. Up to what height, the tumbler is actually filled?

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Vishal Baghel

Contributor-Level 10

As observer is at O So height of water observed by observer

$\Rightarrow \frac{H}{μ_{ω}} = \frac{H}{(4 / 3)} = \frac{3 H}{4}$

given diagram (17.5 H) is height of observer

$S o \frac{3 H}{4} = 17.5 - H$

$\frac{7 H}{4} = 17.5$

7H = 70

H = 10

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