Physics Ray Optics and Optical Instruments

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New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

Please consider the following Image

 

 

New answer posted

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Magnify power of telescope for far point is given as

m = θ i θ 0 = f 0 f e

? θ i = θ 0 f 0 f e = 1 0 100 5 = 20 0

New answer posted

a month ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

For thin prism, deviation = μ - 1 A

New answer posted

a month ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

1 f = 1 v 1 u

1 f = 1 1 0 0 1 5 0 = 1 5 0 1 1 0 0

f = + 1 0 0 c m

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

->Maximum Distance = 3 (x + x) = 6x = 3 * 2x = 3 * 50 = 150 cm

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

Fact based        

 

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a month ago

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A
alok kumar singh

Contributor-Level 10

r ^ i ^ = 2 c o s θ n ^ . . . . . . ( 1 )

r ^ = i ^ 2 ( i ^ . n ^ ) n ^

b = a 2 ( a . c ) c

 

New answer posted

a month ago

0 Follower 6 Views

R
Raj Pandey

Contributor-Level 9

δ t o t a l = 3 6 0 ° 2 θ

= 360 – 2 * 75° = 210°

              Total deviation = δ = 1 5 0 °

 

New answer posted

a month ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

s i n θ C V B = s i n 9 0 ° V A s i n θ C = V B V A = 1 . 5 * 1 0 1 0 2 . 0 * 1 0 1 0 = 3 4

                   

According to question, we can write

  θ > θ = s i n 1 ( 3 4 )

New answer posted

a month ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

Resolving power, = d 1 . 2 2 λ = 2 4 . 4 * 1 0 2 1 . 2 2 * 2 4 4 0 * 1 0 1 0  

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