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New answer posted
10 months agoContributor-Level 10
hc/λ = K? + φ [given φ is negligible]
So, hc/λ = K?
λ? = h/√ (2mK? ²) ⇒ K? = h²/ (2mλ? ²)
(hc)/λ = h²/ (2mλ? ²) ⇒ λ = (2mc/h)λ? ²
New answer posted
10 months agoContributor-Level 10
Least count = 1 mm / 100 = 0.01 mm
Diameter = main scale reading + circular scale reading
Diameter = 0 + 52 * 0.01 mm
= 0.52 mm = 0.052 cm
New answer posted
10 months agoContributor-Level 9
Theory based
Capacitor in parallel removes the AC ripple from the rectified output.
New answer posted
10 months agoContributor-Level 10
Least count = 1 mm / 100 = 0.01 mm
Diameter = main scale reading + circular scale reading
Diameter = 0 + 52 * 0.01 mm
= 0.52 mm = 0.052 cm
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