Physics

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New answer posted

a year ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

E = ½CV²
= ½ (ε? A/d)Ed²
= ½ε? E²Ad

New answer posted

a year ago

0 Follower 10 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

a year ago

0 Follower 31 Views

R
Raj Pandey

Contributor-Level 9

Let height of bridge = h

Displacement of ball, S = - h

S = u t + 1 2 a t 2 - h = 4 * 4 + 1 2 ( - 10 ) ( 4 ) 2 ⇒ h = 64 m

New answer posted

a year ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

Factual (theory based)

New answer posted

a year ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

Least count = 1 mm / 100 = 0.01 mm
Diameter = main scale reading + circular scale reading
Diameter = 0 + 52 * 0.01 mm
= 0.52 mm = 0.052 cm

New answer posted

a year ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

Theory based

Capacitor in parallel removes the AC ripple from the rectified output.

New answer posted

a year ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

N N 0 = 1 16 = 1 2 t T 1 / 2

t = 4 T 1 / 2 = 20 * 4 = 80   minutes  

New answer posted

a year ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Least count = 1 mm / 100 = 0.01 mm
Diameter = main scale reading + circular scale reading
Diameter = 0 + 52 * 0.01 mm
= 0.52 mm = 0.052 cm

New answer posted

a year ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

? 1 λ = R 1 n 2 2 - 1 n 1 2

⇒ 1 λ = R 1 2 2

⇒ λ = 4 R

1 λ ' = R 1 4 2

⇒ λ ' = 16 R

⇒ λ ' = 4 λ

New answer posted

a year ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

Incident energy = 2.20 e V

If ? < 2.20 e V  electron will emit.

? > 2.20 e V No electron emission

Only caesium will emit electron

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