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New answer posted

4 months ago

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R
Raj Pandey

Contributor-Level 9

Initial velocity = - v j ˆ

Final velocity = - v j ˆ  

Change in velocity = v i ˆ - ( - v j ˆ )

= v ( i ˆ + j ˆ ) Momentum gain is along i ˆ + j ˆ

Force experienced is along i ˆ + j ˆ

Force experienced is in North-East direction.

New answer posted

4 months ago

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R
Raj Pandey

Contributor-Level 9

Average speed = 4 v 2 3 v

= 4 v 3

New answer posted

4 months ago

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R
Raj Pandey

Contributor-Level 9

m = ρ π r 2 1

ρ = m π r 2 1 Δ ρ ρ = Δ m m + 2 Δ r r + Δ l 1 Δ ρ ρ * 100 = 0.002 0.4 * 100 + 2 * 0.001 0.3 * 100 + 0.02 5 * 100 = 0.2 0.4 + 0.2 0.3 + 2 5 = 0.5 + 0.67 + 0.4 = 1.57 = 1.6 %

New answer posted

4 months ago

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R
Raj Pandey

Contributor-Level 9

As the factors controlling temperature and voltage supply are beyond prediction and control so the error occurred due to unpredictable fluctuations of temperature and voltage would be random errors.

New answer posted

4 months ago

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A
alok kumar singh

Contributor-Level 10

A reverse-biased Zener diode is used as a voltage regulator.
The potential barrier for Germanium (Ge) is approximately 0.3 V.
The potential barrier for Silicon (Si) is approximately 0.7 V.

New answer posted

4 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

4 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

New answer posted

4 months ago

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A
Aadit Singh Uppal

Contributor-Level 10

Yes, an object moving in a straight path can also possess angular momentum with respect to a referenc epoint which doesn't lie on it's path. In such cases. the referenc epoint may lie perpendicular distance from the axis. If an object is moving in a straight line (not through the reference point) the perpendicular distance r? r_\perp (l = rp) will be non-zero.

New answer posted

4 months ago

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A
Aadit Singh Uppal

Contributor-Level 10

Yes, how much time these planets take in completing an orbit around the sun hugely depends on their distance from the sun as well as their mass. Since these planets move in a circular orbit, the term angular momentum is used in such cases for computing relevant information.

New answer posted

4 months ago

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A
Aadit Singh Uppal

Contributor-Level 10

Angular momentum also depends on how the mass is spread over the body and not just mass only. If you closely look at the formula of angular momentum:

L=r*p

You will observe that it is a cross product of two vector quantities. Hence, the formula won't be practical without direction being involved. 

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