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New answer posted
7 months agoContributor-Level 10
Surprisingly, the viscosity of a dilute gas behaves exactly opposite to what you might expect for liquids. Liquid viscosity generally decreases as temperature is lowered. The viscosity of a dilute gas increases as and when you raise its temperature. This counter-intuitive behaviour was clearly established experimentally and is explained by the kinetic theory.
New answer posted
7 months agoContributor-Level 10
It's because gas molecules constantly move around at super high speeds. They randomly bump into each other constantly. Gravity does pull on them. The pulling effect is not much, however. When we consider the distance from the floor to the ceiling, gravity's pull is overcome by the molecular kinetic energy. So they just spread out and move from one place to another. They can't settle down.
New answer posted
7 months agoContributor-Level 10
P = constant
m (dv/dt) = P
∫? vdv = P/m ∫? dt
v²/2 = Pt/m ⇒ v = (2Pt/m)¹/²
dx/dt = √ (2P/m) t¹/²
∫? dx = √ (2P/m) ∫? t¹/² dt
x = √ (2P/m) (t³/² / (3/2) = √ (2P/m) * (2/3) * t³/²
= (2/3) * 27 = 18
New answer posted
7 months agoContributor-Level 10
V_rms = √ (3RT/M)
V_N? = V_H?
√ (3RT_N? / M_N? ) = √ (3RT_H? / M_H? )
573/28 = T_H? /2
⇒ T_H? = 40.928
New answer posted
7 months agoContributor-Level 10
E? = φ + K?
E? = φ + K?
E? - E? = K? - K?
Now V? /V? = 2
K? /K? = 4; K? = 4K?
Now from equation (2)
⇒ 4 - 2.5 = 4K? - K?
1.5 = 3K?
K? = 0.5eV
Now putting this
Value in equation (2)
2.5 = φ + 0.5eV
φ = 2eV
New answer posted
7 months ago
Contributor-Level 10
L_i = L_f
mvL = Iω
mvL = (ML³/3 + mL²)ω
Before collision
After collision
0.1 * 80 * 1 = (0.9 * 1²)/3 + 0.1 * 1²)ω
8 = (3/10 + 1/10)ω 8 = (4/10)ω ω = 20 rad/sec
New answer posted
7 months agoContributor-Level 10
Let us assume the potential at A = V_A = 0.
Now at junction C, according to KCL
i? + i? = i?
1 A + i? = 2 A
i? = 2 A
Now analyse potential along ACDB
V_A + 1 + i? (2) - 2 = V_B
0 + 1 + 2 (1) - 2 = V_B
V_B = 3 - 2
V_B = 1amp.
New answer posted
7 months agoContributor-Level 10
x = 1/√ (µ? ε? ) = speed ⇒ [x] = [L¹T? ¹]
y = E/B = speed ⇒ [y] = [L¹T? ¹]
z = l/ (RC) = l/τ ⇒ [z] = [L¹T? ¹]
So, x, y, z all have the same dimensions.
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