Physics

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New answer posted

7 months ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

Magnetic energy per unit volume = B 2 2 μ 0

New answer posted

7 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

I = I 0 c o s 2 ? θ

I 0 10 = I 0 c o s 2 ? θ

c o s ? θ = 1 10 = 0.31 < 1 2 which is 0.707

So, θ > 45 ?  and 90 - θ < 45 ?  so only one option is correct i.e. 18.4 ?

Angle rotated should be = 90 ? - 71.6 ? = 18.4 ?  .

New answer posted

7 months ago

0 Follower 7 Views

R
Raj Pandey

Contributor-Level 9

( 0,3 )

r ? c m = 1 * i ˆ 2 + j ˆ + 1 * i ˆ + 5 j ˆ 2 2 r ? c m = 3 4 i ˆ + 7 4 j ˆ

( 0,0 )

New answer posted

7 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

W equator   = W pole   - m ω 2 R

= 196 - 19.6 * 2 π 24 * 60 * 60 2 * 6400 * 10 3 = 195.33 N

New answer posted

7 months ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

New answer posted

7 months ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

m ? 2 ( l + x ) = k x

l x + 1 = k m ? 2 x = l m ? 2 k - m ? 2

 

New answer posted

7 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

W = Q 1 - Q 2 = Q 2 - Q 3

Q 2 = Q 1 + Q 3 2

2 = Q 1 Q 2 + Q 3 Q 2

2 = T 1 T + T 2 T

T = T 1 + T 2 2

New answer posted

7 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

At any time t

? = B A c o s ? π t 5 ? ω = 2 π T = 2 π 10 = π 5

d ? d t = - π 5 B A s i n ? π t 5

e = π 5 B A s i n ? π t 5

e will be maximum when π t 5 is π 2

t = 2.5 s e c

e will be minimum when π t 5 is π , 0

t = 0,5 s e c

So, answer will be (1).

New answer posted

7 months ago

0 Follower 18 Views

R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

New answer posted

7 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Moment of inertia of ring

d l = d m r 2

I = 0 a ? ( A + B r ) 2 π r d r π r 2

= 2 π A 0 a ? r 3 d r + 2 π B 0 a ? r 4 d r

= 2 π A a 4 4 + B a 5 5

= 2 π a 4 A 4 + B a 5

 

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