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New answer posted

4 months ago

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V
Vishal Baghel

Contributor-Level 10

  I = I 0 t - I 0 t 2

? = B A

? = μ 0 n I A

V R = d ? d t = - μ 0 n A l 0 ( 1 - 2 t )

V R = 0 at   t = 1 2 and I R = V R   Resistance of loop  

 

New answer posted

4 months ago

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R
Raj Pandey

Contributor-Level 9

Magnitude of electric field is constant & the surface is equipotential.

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4 months ago

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A
alok kumar singh

Contributor-Level 10

  Energy     Volume   = M L 2 T - 2 L 3 = M L - 1 T - 2

The distance between two successive bright fringes is fringe width  ( β ) .

β = λ D d = 589 * 10 - 9 * 1.5 0.15 * 10 - 3 = 5.9 m m

New answer posted

4 months ago

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R
Raj Pandey

Contributor-Level 9

Relation between De-Broglie wavelength and K.E. is

λ = h 2 ( K E ) m e λ 1 K E

λ A λ B = K E B K E 1 2 = T A - 1.5 T A T A 2 e V K E B = 2 - 1.5 = 0.5 e V ? B = 4.5 - 0.5 = 4 e V

New answer posted

4 months ago

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V
Vishal Baghel

Contributor-Level 10

E ? = σ 2 ε 0 c o s ? 60 ? ( - x ˆ ) + σ 2 ε 0 - σ 2 ε 0 s i n ? 60 ? ( y ˆ )

E ? = σ 2 ε 0 1 - 3 2 y ˆ - 1 2 x ˆ

New answer posted

4 months ago

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A
alok kumar singh

Contributor-Level 10

Magnetic energy per unit volume = B 2 2 μ 0

New answer posted

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V
Vishal Baghel

Contributor-Level 10

I = I 0 c o s 2 ? θ

I 0 10 = I 0 c o s 2 ? θ

c o s ? θ = 1 10 = 0.31 < 1 2 which is 0.707

So, θ > 45 ?  and 90 - θ < 45 ?  so only one option is correct i.e. 18.4 ?

Angle rotated should be = 90 ? - 71.6 ? = 18.4 ?  .

New answer posted

4 months ago

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R
Raj Pandey

Contributor-Level 9

( 0,3 )

r ? c m = 1 * i ˆ 2 + j ˆ + 1 * i ˆ + 5 j ˆ 2 2 r ? c m = 3 4 i ˆ + 7 4 j ˆ

( 0,0 )

New answer posted

4 months ago

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A
alok kumar singh

Contributor-Level 10

W equator   = W pole   - m ω 2 R

= 196 - 19.6 * 2 π 24 * 60 * 60 2 * 6400 * 10 3 = 195.33 N

New answer posted

5 months ago

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R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

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