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Physics Class 12th

In the given circuit of potentiometer, the potential difference E across AB (10m length) is larger than E₁ and E₂ as well. For key K₁(closed), the jokey is adjusted to touch the wire at point J₁ so that there is no deflection in the galvanometer. Now the first battery (E₁) is replaced by second battery (E₂) for working by making K₁ open and K₂ closed. The galvanometer gives then null deflection at J₂. The value of $\frac{E_{1}}{E_{2}} i s \frac{a}{b},$ where a = …………….

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Vishal Baghel

Contributor-Level 10

$\frac{E_{1}}{E_{2}} = \frac{380}{760} = \frac{1}{2}$

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Physics Thermodynamics

In a certain thermodynamical process, the pressure of a gas depends on its volume as kV³. The work done when the temperature change from 100°C to 300°C will be……………. nR, where n denotes number of moles of a gas.

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Vishal Baghel

Contributor-Level 10

P = kV³ Þ PV^-3 = k Þ Polytropic Process with index m = -3

W = $\frac{n R (T_{2} - T_{1})}{1 - m} = \frac{n R (300 - 100)}{1 - (- 3)} = 50 n R$ .

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Physics Class 11th

An engine of a train, moving with uniform acceleration, passes the signal – post with velocity u and the last compartment with velocity $υ .$ The velocity with which middle point of the train passes the signal post is:

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Vishal Baghel

Contributor-Level 10

Assume the length of train be I and its acceleration be a.

$v^{2} = u^{2} + 2 a l \Rightarrow a l = \frac{v^{2} - u^{2}}{2}$

Velocity when middle point crosses the post,

$V_{m} = \sqrt[]{u^{2} + 2 a \frac{l}{2}} . = \sqrt[]{u^{2} + \frac{v^{2} - u^{2}}{2}} = \sqrt[]{\frac{u^{2} + v^{2}}{2}}$

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Physics Class 11th

Two satellites A and B of masses 200kg and 400kg are revolving round the earth at height of 600km and 1600km respectively. If T_A and T_B are the time periods of A and B respectively then the value of T_B – T_A :

[Given : radius of earth = 6400km, mass of earth = 6 * 10²⁴kg]

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Vishal Baghel

Contributor-Level 10

$T = 2 π \sqrt[]{\frac{r^{3}}{G M_{e}}}$

$T_{B} - T_{A} = \frac{2 π}{\sqrt[]{G M_{e}}} (r_{B}^{3 / 2} - r_{A}^{3 / 2}) = \frac{2 * 3.14}{\sqrt[]{6.67 * 1 0^{- 11} * 6 * 1 0^{24}}} [{(8 * 1 0^{6})}^{\frac{3}{2}} - {(7 * 1 0^{6})}^{\frac{3}{2}}]$

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Physics Physics Moving Charges and Magnetism

A proton, a deuteron and an α particle are moving with same momentum in a uniform magnetic field. The ratio of magnetic force acting on them is ----------- and their speed is ----------- in the ratio.

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Vishal Baghel

Contributor-Level 10

$v = \frac{p}{m} \Rightarrow v_{p} : v_{d} : v_{α} = 1 : \frac{1}{2} : \frac{1}{4} = 4 : 2 : 1$

$F_{m a g} = q v B \Rightarrow F_{P} : F_{d} : F_{α} = 1 * 4 : 1 * 2 : 2 * 1 = 2 : 1 : 1$

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5 months ago

Physics Dual Nature of Radiation and Matter

Match List – I with List – II :

List – I List – II

(a) h (Planck's constant)

...more

Match List – I with List – II :

List – I List – II

(a) h (Planck's constant) (i) $[M L T^{- 1}]$

(b) E (kinetic energy) (ii) $[M L^{2} T^{- 1}]$

(c) V (electric potential) (iii) $[M L^{2} T^{- 2}]$

(d) P (linear momentum) (iv) $[M L^{2} I^{- 1} T^{- 3}]$

Choose the correct answer from the options given below:

less

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Vishal Baghel

Contributor-Level 10

[h] = ML²T^-1

[E] = ML²T^-2

[V] = ML²T^-2C^-1

[P] = MLT^-1

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5 months ago

Physics Class 11th

A student is performing the experiment of resonance column. The diameter of the column tube is 6cm. THE Frequency of the tuning fork is 504 Hz. Speed of the sound at the given temperature is 336m/s. The zero of the meter scale coincides with tip end of the resonance column tube. The reading of the water level in the column when the first resonance occurs is:

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Vishal Baghel

Contributor-Level 10

For first resonance,

$l + 0.3 d = \frac{v}{4 f}$

$\Rightarrow l + 0.3 * 6 = \frac{336 * 100}{4 * 504} \Rightarrow l = 14.8 c m$

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Physics Class 12th

Magnetic fields at two points on the axis of a circular coil at a distance of 0.05m 0.2m from the centre are in the ratio 8 : 1. The radius of coil is-------------.

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Vishal Baghel

Contributor-Level 10

Magnetic field on the axis of a circular coil at distance x from centre, B = $\frac{μ_{0} N i r^{2}}{2 {(r^{2} + x^{2})}^{\frac{3}{2}}}$ $\frac{_{}^{}}{{^{}^{}}^{\frac{}{}}}$

$\frac{{(r^{2} + {(0.2)}^{2})}^{\frac{3}{2}}}{{(r^{2} + {(0.05)}^{2})}^{\frac{3}{2}}} = 8$ $\frac{r^{2} + {(0.2)}^{2}}{r^{2} + {(0.05)}^{2}} = 4 \Rightarrow r^{2} = 0.01 \Rightarrow r = 0.1 m .$

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Physics Nuclei

Two radioactive substances X and Y originally have N₁ and N₂ nuclei respectively. Half life of X is half of the life of Y. After three half lives of Y, number of nuclei of both are equal.

The ratio $\frac{N_{1}}{N_{2}}$ will be equal to:

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Vishal Baghel

Contributor-Level 10

Number of half lives of Y = 3

Number of half lives of X = 6 [As half life of X is half of that of Y].

$\frac{N_{1}}{2^{6}} = \frac{N_{2}}{2^{3}} \Rightarrow \frac{N_{1}}{N_{2}} = 8$

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5 months ago

Physics Class 11th

If the time period of a two meter long simple pendulum is 2s, the acceleration due to gravity at the place where pendulum is executing S.H.M. is:

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Vishal Baghel

Contributor-Level 10

$T = 2 π \sqrt[]{\frac{l}{g}}$

$\Rightarrow 2 = 2 π \sqrt[]{\frac{2}{g}}$

$\Rightarrow g = 2 π^{2} m / s^{2}$

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