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New answer posted

a year ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

v=ωk=301=30m/s

v=Tμ⇒T=μv2=0.135*10−310−2* (30)2=12.15N=1215*10−2N

New question posted

a year ago

0 Follower 3 Views

New answer posted

a year ago

0 Follower 7 Views

P
Payal Gupta

Contributor-Level 10

l=12cε0E02=η* (P4πr2) Here η is the efficiency

E0=ηP2πr2cε0=1.25100*10002*3.14*4*3*108*8.85*10−12

⇒E0=12.58*3.14*3*8.85*10−4=13.69Vm=136.9*10−1V/m

New answer posted

a year ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

mg – N = ma

N = m (g – a) = 60 * (10 – 1.8) = 60 * 8.2 = 492 N

New answer posted

a year ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Bv = B sin 60°

B v = 2 . 5 * 1 0 − 4 * 3 2

E m f = B v * v * l = 2 . 5 * 1 0 − 4 * 3 2 * 1 8 0 * 5 1 8 * 1 = 1 0 8 . 2 5 * 1 0 − 3 v o l t s

New answer posted

a year ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

U = 3PV + 4

⇒ n   C v T = 3 P V + 4

⇒ n * f R T 2 = 3 P V + 4

⇒ f = 6 + 8 P V

⇒ f > 6 ⇒ p o l y     a t o m i c

New answer posted

a year ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

As we know that Q = ωLR

⇒Q'Q=L'R'*RL= (L'L)* (RR')=2*2⇒Q'=4Q=4*100=400

New answer posted

a year ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

λ = c v = Q 3 W 2 = I 3 T 3 M 2 L 4 T − 4 ⇒ [ λ ] = [ M − 2 L − 4 T 7 l 3 ]                                                                             

 

 

 

New answer posted

a year ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

t a n α = v m a x t 1 = a 1

t a n β = v m a x t 2 = a 2

⇒ a 1 a 2 = t 2 t 1 ⇒ t 1 t 2 = a 2 a 1

New answer posted

a year ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

N = mg + F sin 60°

flim=Fcos60°⇒μN=Fcos60°

μmg=F [cos60°−μsin60°]

F=μmgcos60°−μsin60°=133*3*1012−133*32=10/312−16=10/31/3=10N=3* (103)N

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