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New answer posted

10 months ago

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P
Payal Gupta

Contributor-Level 10

β = λ D d = 5 0 0 * 1 0 9 * 1 2 * 1 0 3 = 2 5 0 * 1 0 6 m = 2 5 0 * 1 0 3 m m = 0 . 2 5 m m

New answer posted

10 months ago

0 Follower 13 Views

V
Vishal Baghel

Contributor-Level 10

N = m g c o s 3 0 ° + q E s i n 3 0 °

a = m g s i n θ q E c o s θ μ N m = 2 . 3 0 m / s 2

S = u t + 1 2 a t 2

t = 2 l a = 1 . 3 1 s e c

New answer posted

10 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

From defined of bulk modulus

K=P (dV/V)....... (1)

m = ρv=constant

ρdV+Vdρ=0

dVV=dρρ......... (2)

With the help of equations (1) and (2), we can write

K=P (dρρ)=ρPdρdρ=ρPK

New answer posted

10 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

Frequency increases on filing. So, initial frequency of A is 335 Hz.

f = 340 – 5 = 335 Hz

New answer posted

10 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Z = R 2 + ( X L X C ) 2

Z = ( 1 2 0 ) 2 + ( 1 0 1 0 0 ) 2 = 1 5 0 Ω

ω = 1 L C = 1 1 0 1 * 1 0 4 = 1 0 5

? ω = 2 π f

f = 1 0 3 2 π 1 0 = 5 0 H z

New answer posted

10 months ago

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V
Vishal Baghel

Contributor-Level 10

A = A 0 e λ t 1 [Radio active decay law]

A 5 = A 0 e λ ( t 2 t 1 )

l n 5 = λ ( t 2 t 1 )

A v e r a g e l i f e = 1 λ = ( t 2 t 1 ) l n 5

New answer posted

10 months ago

0 Follower 35 Views

P
Payal Gupta

Contributor-Level 10

Given circuit can be re-drawn and it becomes case of balanced Wheatstone bride

R A B = ( 2 R ) ( 2 R ) 2 R + 2 R = R

New answer posted

10 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Stress = Y * strain

=> T 1 A = Y * ( l 1 l ) l ( i )

T 2 A = Y * ( l 2 l ) l ( i i )

=> T 1 T 2 = l 1 l l 2 l

l = T 1 l 2 T 2 l 2 T 1 T 2 = T 2 l 1 T 1 l 2 T 2 T 1            

 

New answer posted

10 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

Lyman Series nf = 1, ni = 2, 3.

Paschen series nf = 3, ni = 4, 5, 6 -

1λ1=RZ2 (112142)

1λ2=RZ2 (132142)

1/λ11/λ2=111619116λ2λ1=151679*16=15*97λ1λ2=7135

New answer posted

10 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

l=l1sinωt+l2cosωt=l12+l22 [ (l1l12+l22)sinωt+l2l12+l22cosωt]

=l12+l22sin (ωt+α)=l0sin (ωt+α

l r m s = l 0 2 = l 1 2 + l 2 2 2

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