Physics

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New answer posted

a year ago

0 Follower 8 Views

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Payal Gupta

Contributor-Level 10

Since force will act in horizontal direction so vertical component of speed will be same

v1 cos α = v2 cos β

⇒ K 1 K 2 = ( v 1 v 2 ) 2 = c o s 2 β c o s 2 α

New answer posted

a year ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

In ferromagnetic material, below Curie's temperature, a domain is defined as macroscopic region with zero magentisation.

New answer posted

a year ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

Using Bohr's theory :

λ=hcE2−E1=1242eV−nm (−3.4)− (−13.6)=121.8nm

New answer posted

a year ago

0 Follower 8 Views

P
Payal Gupta

Contributor-Level 10

Using conservation of energy between initial and final position shown :

[12 (25ma2) (V0a)2+12mV02]+0=mglsinθ

⇒710mV02=mglsinθ

⇒l=7v0210gsinθ

New answer posted

a year ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

Using de-Broglie equation for wave nature of particle :

λ=hcmv⇒λα1m

λeλP=1me1mP=mPme=1836

New answer posted

a year ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

Using diffraction formula of circular hole :

rα1D

size will decease.

New answer posted

a year ago

0 Follower 4 Views

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Payal Gupta

Contributor-Level 10

λ a i r = c f c

New answer posted

a year ago

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Payal Gupta

Contributor-Level 10

Put one part of shaded region to another side, shape becomes.

? =q24ε0

New answer posted

a year ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

Translational kinetic energy will be equal to rotational kinetic energy corresponds to each degree of freedom.

New answer posted

a year ago

0 Follower 19 Views

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Payal Gupta

Contributor-Level 10

When second stone is released

Equation for first ball:

x+20=10t+12gt2

Equation for second ball :

x=12gt2

Using these two equation

20 = 10t t = 2 sec

x=12*10*4=20m

H = 20 + 20 + 5 = 45 m.

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