Physics

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New answer posted

5 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

λ 4 = l λ = 4 l

f = v λ = v 4 l l = v 4 f
l = 3 4 4 * 2 5 = 0 . 3 4 m = 3 4 c m

 

New answer posted

5 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

Q = CV

= ( 5 0 μ F ) * 2 V

= 1 0 0 * 1 0 6 C

Q = 1 0 0 μ C (on upper plate)

New answer posted

5 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

  B = E c = 6 3 * 1 0 8 = 2 * 1 0 8 T            

->x = 2

New answer posted

5 months ago

0 Follower 15 Views

R
Raj Pandey

Contributor-Level 9

θ = 6 0 ° 2 = 3 0 °

 

New answer posted

5 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

R e q = 3 Ω

 

New answer posted

5 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution 

  T 1 4 0 0 = 3 0 0 2 4 0 T 1 = 5 0 0 K

New answer posted

5 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

  R e q = 6 ?

i = 1 2 v 6 Ω 2 A (through battery)

v 1 5 Ω = 6 V

New answer posted

5 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

When switch is open,

R e q = 3 R 2              

When switch is closed,

R e q ' = 2 * R * 2 R R + 2 R = 4 R 3           

R e q R e q ' = 3 R / 2 4 R / 3 = 9 8 = x 8

x = 9

 

New question posted

5 months ago

0 Follower 2 Views

New answer posted

5 months ago

0 Follower 10 Views

A
alok kumar singh

Contributor-Level 10

Time taken by first drop to reach the ground,

t 1 = 2 h g = 2 * 9 . 8 9 . 8 = 2 s              

Time for which second drop has fallen,

t 2 = t 1 t 1 2 = 2 1 2 s

Height of the second drop

= 9 . 8 1 2 * 9 . 8 * ( 2 1 2 ) 2 = 7 . 3 5 m

              

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