Physics

Kindly go through the solution

Based on theory

B_v = 6 * 10^-5 T

B_v = B_N sin37°

$\therefore B_N=\frac{B_v}{sin37°}=\frac{6*10^{-5}}{3/5}=10^{-4}T$

W_total = W_D→E + W_E→F = Area of triangle DEF

= $\frac{1}{2}*3*300=450J.$

We know, R = R_oA₃₌

_{$\Rightarrow \frac{R}{R_O}=A^3$}

Taking log both side

$lo{g}_e\left(\frac{R}{R_O}\right)=3logA$                

$\lambda =\frac{h}{mv}=\frac{h}{\sqrt[]{2mk.E}}$

$\lambda \alpha \frac{1}{\sqrt[]{m}}$

$m_{\alpha }>m_n>m_p>m_e$

${\lambda }_{\alpha }<{\lambda }_n<{\lambda }_p<{\lambda }_e$  

A ring magnet is a type of strong and permanent magnet which is made from the alloy of iron, boron and neodymium. These are the part of rare-earth magnet family which is the reason behind their the strongest magnetic properties amongst all other permanent magents.

A U-shaped magnet is another type of bar magnet. This is known as a horseshoe magnet since its shapes resembles the object called horseshoe. The two ends of this U-shaped magnet are its magnetic poles. Configration of these magnetic poles creates a concentrated magnetic field. This concentrated magnetic field makes it much more stronger than a simple and straight bar magnet.

Kindly go through the solution

Based on theory.

$\frac{l_1}{l_2}=\frac{4}{1}$                

$\Rightarrow l_{max}={\left(\sqrt[]{l_1}+\sqrt[]{l_2}\right)}^2=l_1+l_2+2\sqrt[]{l_1{l}_2}$

$\Rightarrow \frac{l_{max}+l_{min}}{l_{max}-l_{min}}=\frac{5}{x}$

$\Rightarrow \frac{1}{2}*\frac{l_2\left(1+\frac{l_1}{l_2}\right)}{\sqrt[]{l_1{l}_2}}=\frac{5}{x}$

$\Rightarrow \frac{1}{2}\frac{1}{\sqrt[]{4}}=\frac{1}{x}\Rightarrow x=4$               

When electric field vector is completely removed and incident on Brewster's angle then only refraction takes place.