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New answer posted

6 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Energy released = Binding energy of product – Binding energy of reacts :

ΔE=7.6*4 (1.1*4)

= 26 MeV

New answer posted

6 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

For first line of Lyman

1λ=R (114)=R34

λ=43R

3rd line (Paschen)

1λ3=R (132162)=R9*34

2nd line (B almer)

1λ2=R (122142)=R4*34

a (43R)=203Ra=5

New answer posted

6 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

For point B, 1u=0.10cm1, 1v=0

Thus u = 10 cm, v = 

i.e., f = 10 cm

110= (1.51) (2R)1R=110

R = 10 cm

New answer posted

6 months ago

0 Follower 19 Views

V
Vishal Baghel

Contributor-Level 10

At very high frequencies

XC=1ωC0

XL=ωL

Thus equivalent circuit

Z=1+2+2=5Ω

l=2205=44A

New answer posted

6 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

1.5 * sin 60 = R * sin 90

1.5*32=n=x4

x = 27

New answer posted

6 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

 k=lm=ml2/12m=l23

k=10323=5

New answer posted

6 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Initially,  PQ=4060=23 - (1)

Finally,  P+xQ=8020=41

(2) (1)

P+xP=4*32=6

1+xP=6

xP=5

x = 5 P = 5 x 4 = 20 Ω

New answer posted

6 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Component of A along B = A.B|B|

= 2

New answer posted

6 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

Capacitance of each capacitor

C1=A3ε012=6Aε0

C2=A4ε0=4Aε0

Equivalent capacitance

Δv2=240Aε04Aε0=60v

vfoil=60v

New answer posted

6 months ago

0 Follower 8 Views

A
alok kumar singh

Contributor-Level 10

Breading stress = WeightArea

102.5*10.4=25A

A=6.25*104m2

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