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New answer posted

12 months ago

0 Follower 14 Views

V
Vishal Baghel

Contributor-Level 10

Capacitance of each capacitor

C1=A3ε012=6Aε0

C2=A4ε0=4Aε0

Equivalent capacitance

Δv2=240Aε04Aε0=60v

vfoil=60v

New answer posted

12 months ago

0 Follower 11 Views

A
alok kumar singh

Contributor-Level 10

Breading stress = WeightArea

102.5*10.4=25A

A=6.25*104m2

New answer posted

12 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

 f1=100=fo (CCVS)

C = Speed of sound

Vs = Speed of source

f2 = 50 = fo = (CC+Vs)

f1f2=2=C+VSCVS

fo=2003=x3

x = 200

New answer posted

12 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

R=R? A1/3

δ=massvolume=mA43πR3=mA4/3πR03A

 Density is independent of mass number

New answer posted

12 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

L = 1 m

ΔL=0.4*103m

m=1kg

d = 0.4 * 10-3 m

FA=yΔLL

y=FLAΔL= (mg)*1 (πd24)*0.4*103

Δy=0.1*0.199*1012=1.99*1010

= 1.99

New answer posted

12 months ago

0 Follower 11 Views

A
alok kumar singh

Contributor-Level 10

 a1=m2gm1gm1+m2=2mgmg3m=g3

a2=3mgmg4m=g2

a1a2=23

New answer posted

12 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Loss in P.E. = Gain in k.E

2 mg R = 12 (12mR2+mR2)ω2

ω=8g3R=4g2*3R

x=g2=5

New answer posted

12 months ago

0 Follower 11 Views

V
Vishal Baghel

Contributor-Level 10

y = x5 (1 - x) = x tanθ  (1xR)

tan = 5, R = 1

sinθ=526, cosθ=126

R=u2sin2θg=1

u2=26u=26m/s

y - component of initial velocity

= u sinθ 

=26*526

= 5 m/s

New answer posted

12 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

KE=728*1.6*1019=12*9.1*1031*V2

V = 16 * 106 m/s

For Lorentz force to be zero

eE = eVB

E=vB=16*106*12*103

= 192 * 103 V/m

New answer posted

12 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

 M=IA1IA2

M=7*227* [251009100]k^

M=72k^Am2

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