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6 months ago

Physics Physics NCERT Exemplar Solutions Class 12th Chapter Twelve

A monoatomic gas at pressure P and volume V is suddenly compressed to one eight of its original volume. The final pressure at constant entropy will be:

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Vishal Baghel

Contributor-Level 10

Constant Entropy means Adiabatic process

$P v^{y} = C$

$P_{1} {v_{1}}^{y} = P_{2} {v_{2}}^{y}$

$P_{2} = P_{1} {(\frac{v_{1}}{v_{2}})}^{y} = P {(\frac{v}{\frac{1}{8} v})}^{y}$

$P_{2} = P (8) \frac{5}{3}$

P₂ = 32 P

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6 months ago

Physics Thermodynamics

The volume V of a given mass of monoatomic gas changes with temperature T according to the relation $V = k T^{\frac{2}{3}} .$ The work done when temperature changes by 90 K will be xR. The value of x is…….

[R = universal gas constant]

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Payal Gupta

Contributor-Level 10

$V = k T^{\frac{2}{3}}$

$T V^{- \frac{3}{2}} = K$

$\Rightarrow γ - 1 = - 3 / 2$

$\Rightarrow γ = - 1 / 2$

Work done = $\frac{n R Δ T}{- y + 1} = \frac{1 * R * 90}{3 / 2} = 6 R$

n = 60

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6 months ago

Physics Physics NCERT Exemplar Solutions Class 12th Chapter Twelve

7 mol of a certain monoatomic ideal gas undergoes a temperature increase of 40K at constant pressure. The increase in the internal energy of the gas in this process is:

(Given R = 8.3 JK^-1 mol^-1)

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Vishal Baghel

Contributor-Level 10

$Δ u = n C_{V} Δ T$

$= n \frac{3 R}{2} Δ T$

$= 7 * \frac{3}{2} * 8.3 * 40$

$= 3486 J$

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6 months ago

Physics Oscillations

Time period of a simple pendulum is T. The time taken to complete $\frac{5}{8}$ oscillations starting from mean position is $\frac{α}{β} T .$ The value of a is

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Payal Gupta

Contributor-Level 10

Total oscillation = $\frac{1}{2} + \frac{1}{8} = \frac{5}{8}$

$\Rightarrow t i m e t a k e n = \frac{T}{2} + \frac{T}{12} = \frac{7 T}{12}$

= 7

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6 months ago

Physics Physics NCERT Exemplar Solutions Class 12th Chapter Fourteen

When a particle executes Simple Hormonic Motion, the nature of graph of velocity as a function of displacement will be:

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Vishal Baghel

Contributor-Level 10

x = A sin $ω t$

$\Rightarrow v = A ω c o s ω t$

$\Rightarrow v = \pm ω \sqrt[]{A^{2} - x^{2}}$

$\frac{v^{2}}{ω^{2}} + x^{2} = A^{2}$

Elliptical

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6 months ago

Physics Physics NCERT Exemplar Solutions Class 12th Chapter Nine

A body is projected vertically upward from the surface of earth with a velocity equal to one third of escape velocity. The maximum height attained by the body will be:

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alok kumar singh

Contributor-Level 10

$V_{C} = \sqrt[]{\frac{2 G M}{R}}$

Using conservation of Mechanical Energy

$\Rightarrow \frac{- G M m}{R} + \frac{1}{2} * m (\frac{V e^{2}}{9}) = \frac{- G M m}{(R + h)}$

$\Rightarrow \frac{1}{R + h} = \frac{8}{9 R} \Rightarrow h = \frac{R}{8} = \frac{6400}{8} = 800 k m$

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6 months ago

Physics physics ncert exemplar solutions class 12th chapter two

The total charge on the system of capacitors $C_{1} = 1 μ F, C_{2} = 2 μ F, C_{3} = 4 μ F a n d C_{4} = 3 μ F$ connected in parallel is:

(Assume a battery of 20V is connected to the combination)

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Vishal Baghel

Contributor-Level 10

$C_{e q} = C_{1} + C_{2} + C_{3} + C_{4}$

= 1 + 2 + 4 + 3

$= 10 ? F$

Q = C_eq v

= (10 x 20) $? C$

Q = 200 $? C$

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6 months ago

Physics Physics NCERT Exemplar Solutions Class 12th Chapter Nine

Light travels in two media M₁ and M₂ with speeds 1.5 * 108 ms1 and 2.0 * 108 ms1 respectively. The critical angle between them is:

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alok kumar singh

Contributor-Level 10

$s i n i_{C} = \frac{μ_{r a r e r}}{μ_{d e n e r}} = \frac{v e l o c i t y o f r o r e r}{v e l o c i t y o f d e n s e r}$

$\Rightarrow s i n i_{c} = \frac{1.5 * 1 0^{8}}{2 * 1 0^{8}} = \frac{3}{4}$

$\Rightarrow t a n i_{c} = \frac{3}{\sqrt[]{7}}$

$\Rightarrow i_{c} = t a n^{- 1} (\frac{3}{\sqrt[]{7}})$

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6 months ago

Physics Electromagnetic Waves

The oscillating magnetic field in a plane electromagnetic wave is given by $B_{y} = 5 * 1 0^{- 6} s i n 100 π (5 x - 4 * 1 0^{8} t) T .$ The amplitude of electric field will be:

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alok kumar singh

Contributor-Level 10

$B_{0} = 5 * 1 0^{- 6}$

Speed of wave V = $\frac{4 * 1 0^{8}}{5} = 8 * 1 0^{7}$

$E ? = V * B ? = 4 ? * 10 = 4 * 1 0^{2} V / m$

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6 months ago

Physics Communication Systems

Draw the output signal Y in the given combination of gates.

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Payal Gupta

Contributor-Level 10

$y = \bar{\bar{A} + B} = A . \bar{B}$

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