Physics

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New answer posted

7 months ago

0 Follower 4 Views

P
Pallavi Pathak

Contributor-Level 10

Yes, if one practices from the NCERT Exemplar, they can score high in the CBSE Board exams and entrance exams like NEET and JEE. The exemplar questions include advanced and application-based questions which deepen students' understanding of key concepts. It contains information beyond the NCERT textbook and offers concept clarity to students. Practicing from the exemplar helps in improving the problem-solving skills of the students.

New answer posted

7 months ago

0 Follower 4 Views

P
Pallavi Pathak

Contributor-Level 10

Motion in a Straight Line focuses on the rectilinear motion, which is the motion of objects along a single straight path. It covers key concepts such as speed, displacement, acceleration, velocity, and motion graphs. It helps students understand more complex types of motions.

New answer posted

7 months ago

0 Follower 1 View

P
Pallavi Pathak

Contributor-Level 10

If one solves all these questions then it is great but it is not something mandatory. Practicing these questions helps students develop a strong understanding of Coulomb's law, electric charges, the superposition principle, and electric field lines. Even practicing a significant portion helps in boosting exam confidence and helps students to score high in the examination.

New answer posted

7 months ago

0 Follower 9 Views

P
Pallavi Pathak

Contributor-Level 10

The NCERT textbook is good to start with as it introduces students to the basic concepts and explains these topics to provide conceptual clarity. However, the exemplar focuses on reasoning, challenging multiple-choice questions and numerical problems. The exemplar is like the supplement that boosts students' grasp on these concepts given in the NCERT textbook through reasoning, multiple-choice and numerical problems.

New answer posted

7 months ago

0 Follower 5 Views

P
Pallavi Pathak

Contributor-Level 10

Chapter 1 Electric Charges and Fields NCERT Exemplar goes beyond the basic NCERT textbook and contains application-based and advanced-level questions. It is designed to enhance students' problem-solving skills, improve their understanding of electrostatics, and prepare them for their CBSE board exams and competitive exams like NEET and JEE.

New answer posted

7 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- (a, d)

Explanation- In reverse biasing, the minority charge carriers will be accelerated due to reverse biasing, which on striking with atoms cause ionization resulting secondary electrons and thus more number of charge carriers.

When doping concentration is large, there will be large number of ions in the depletion

region, which will give rise to a strong electric field.

New answer posted

7 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- a, c, d

Explanation-ripple factor is inversely proportional to RL, C  and frequency. so to reduce ripple factor all these should be increase.

New answer posted

7 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer-b, d

Explanation- During regulation action of a Zener diode, the current through the Rs changes and resistance offered by the Zener changes. The current through the Zener changes but the voltage across the Zener remains constant.

New answer posted

7 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- a, b, d

Explanation- The space-charge regions on both the sides of p-n junction which has immobile ions and entirely lacking of any charge carriers will form a region called depletion region of a diode.

The number of ionized acceptors on the p -side equals the number of ionized donors on the n-side.

New answer posted

7 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- b, c

Explanation- IC= 10mA

Ic= 95/100  Ie

Ie= 10 * 100 95 = 10.53mA

Ib=Ie-IC= 10.53-10= .53mA

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