Physics Waves

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New answer posted

a year ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

f ' = f ⌊ v + v 4 v ⌋ = 5 f 4

⇒ f ' f = 5 4

⇒ Δ f f = 1 4

New answer posted

a year ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

Equation of component waves are

y = Asin (ωt – kx) and y = Asin (ωt + kx)

So speed of component wave is ω/k

New answer posted

a year ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Frequency increases on filing. So, initial frequency of A is 335 Hz.

f = 340 – 5 = 335 Hz

New answer posted

a year ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

| f 1 − f 2 | = 4 0 1 2 = 1 0 3

⇒ v ( 1 λ 1 − 1 λ 2 ) = 1 0 3

⇒ V = 1 0 3 * λ 1 λ 2 λ 2 − λ 1 = 1 0 3 * 4 . 0 8 * 4 . 1 6 . 0 8 = 1 0 3 * 4 0 8 * 4 . 1 6 8 = 7 0 7 . 2 m / s

 

New answer posted

a year ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Answer (3) 

Particles having phase difference of ? will move with same speed.

New answer posted

a year ago

0 Follower 57 Views

V
Vishal Baghel

Contributor-Level 10

v = ω k = 5 π * 3 0 π = 1 5 0 = T 1 1 0 0

⇒ T = 2 2 5 0 0 0 0 1 0 0 = 2 2 5 N

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

Δν = 2f? (Δl? + Δl? ) = 2 * 300 (0.1 + 0.1) * 10? ² = 1.2 m/s

New answer posted

a year ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

f? = f? (330/ (330-V) f? = f? (330/ (330+V)
(f? - f? )/f? * 100 = 2% ⇒ (330/ (330-V) - (330/ (330+V) = 0.02
⇒ 330 [ (2V)/ (330)²-V²)] = 0.02 ⇒ 330V = 0.01 * (330)² ⇒ V = 3.3 m/s (approx.)

New answer posted

a year ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

V = γ R T M ,  where,  T = T 1 + T 2 - T 1 d x

Also, v = γ R 273 M ⇒ γ R M = v 273

Also, V = d x d t = γ R T M ⇒ ∫ 0 d ? d x T 1 + T 2 - T 1 d x = γ R M ∫ 0 t ? d t

 

⇒ t = 273 v ⋅ 2 d T 2 - T 1 T 2 - T 1 ∴ t = 2 d v 273 T 1 + T 2

New answer posted

a year ago

0 Follower 21 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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