Physics Waves

  $f_1=f_o\left(\frac{v}{v-v_s}\right)\mathrm{}{f}_1-f_2=2$

$f_2=f_o\left(\frac{v}{v+v_s}\right)\mathrm{}{f}_{0}v\left[\frac{v+v_s-\left(v-v_s\right)}{v^2-v_s^2}\right]=2;\mathrm{}\frac{2f_{0}v{v}_s}{v^2-v_s^2}=2$

$?{\mathrm{v}}_{\mathrm{s}}?\mathrm{v}\mathrm{}\therefore {\mathrm{v}}_{\mathrm{s}}=\frac{1}{4}\mathrm{m}/\mathrm{s}$

$v=\frac{\omega }{k}=\frac{30}{1}=30m/s$

$v=\sqrt[]{\frac{T}{\mu }}\Rightarrow T=\mu v^2=\frac{0.135*10^{-3}}{10^{-2}}*{\left(30\right)}^2=12.15N=1215*10^{-2}N$

$v=\sqrt[]{\frac{T}{\mu }}$

new v' = $\sqrt[]{\frac{1.04T}{\mu }}$

% change = $\left(\sqrt[]{1.04}-1\right)*100$

= 2%

Initially wall will act as observer, so with the help of Doppler's effect, we can write

$f\text{'}=\frac{c}{c-v_0}{f}_0$  

Now wall will act as source of sound of frequency f', so With the help of Doppler's effect, we can write

$f\text{'}\text{'}=\frac{c+v_0}{c}{f}^{\text{'}}=\frac{c+v_0}{c-v_0}{f}_0$              

$\Rightarrow 500=\left(\frac{c+v_0}{c-v_0}\right)400\Rightarrow 5c-5v_0=4c+4v_0\Rightarrow v_0=\frac{c}{9}=\frac{330}{9}m/s=\frac{330}{9}*\frac{18}{5}km/h=132km/h$

The equation of wave at any time t will be $y=\frac{1}{1+{\left(x?vt\right)}^2},$ so v * 1 = 2 -> v = 2m/s

The main difference lies in the direction. We should know that in a longitudinal wave, the displacement of particles is parallel to the direction of wave propagation. In a transverse wave, however, the displacement is perpendicular to the direction of wave propagation.

The units of angular wave number and angular frequency are slightly different.

• Angular wave number k has units of radian per metre (rad/m).
• Angular frequency has units of radian per second (rad/s).

In Physics, we need to know that the phase angle tells us the position of a point within one cycle of a wave. That is measured in radians. It tells you how much a wave is ahead or, behind the other. On the other hand, the initial phase (or phase constant) is the phase angle at time t=0. It tells us where the wave begins with its oscillation cycle.