Redox Reactions
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New answer posted
a month agoContributor-Level 10
The reaction is: FeCl? + 3H? C? O? + 3KOH → K? [Fe (C? O? )? ] (A) + 3HCl + 3H? O
In the complex [Fe (C? O? )? ]³? , the oxalate ion (C? O? )²? is a bidentate ligand.
There are three bidentate ligands, so the coordination number, or secondary valency, of Fe is 3 * 2 = 6.
New answer posted
a month agoContributor-Level 10
Cr? O? ²? + Fe²? - (H? )-> Cr³? + Fe³?
(n=6) (n=1)
Meq Cr? O? ²? = Meq Fe²?
20 * 0.03 * 6 = 15 * M * 1
M = (20 * 0.03 * 6) / 15 = 0.24 = 24 * 10? ²
Ans = 24
New answer posted
a month agoContributor-Level 9
eq of H? O? = eq of KMnO?
(0.316 / 158) x 5 = 0.01
(0.01 x 17 / 0.2) x 100 = 85%
New answer posted
a month agoContributor-Level 10
(i) 2Fe²? + H? O? → 2Fe³? + 2OH?
(ii) 2MnO? + 5H? O? + 6H? → 2Mn²? + 5O? + 8H? O
So sum of (x + y + x¹ + y¹ + z¹) = 2 + 2 + 2 + 5 + 8 = 19
New answer posted
a month agoContributor-Level 9
2 Pb (NO? )? → 2PbO + 2NO? + O?
2NO? → N? O? colourless
N? O? + 2NO → 2 N? O?
Oxidation state in N? O? is +3
New answer posted
a month agoContributor-Level 10
Toilet cleaner is acidic (HCl). Neutralize with weak base NaHCO?
New answer posted
a month agoContributor-Level 10
rate=k [Conc]? log [rate]=logk+nlog [Conc]. 'n' is slope. Higher slope, higher order.
New question posted
a month agoNew question posted
a month agoNew answer posted
a month agoContributor-Level 10
50.00
K? Cr? O? + FeC? O? → Fe³? + CO? + Cr³? + K? + H? O
n_f=6 n_f=3
Now apply equivalent concept
0.02 * 6 * V = (0.288 / (144/3) * 10³
Normality
V = (0.288 * 10³)/ (48 * 6 * 0.02) = 50.00 mL
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