Solid State
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New answer posted
2 months agoContributor-Level 10
Since, atom B forms CCP structure. Therefore, there will be 4-B atoms.
Now, atom A occupies 1/3 of tetrahedral voids.
Hence, number of A atoms = 1/3 * 8 = 8/3
The correct formula of the compound = A? /? B?
= A? B?
x + y = 2 + 3 = 5
New answer posted
2 months agoContributor-Level 10
n (O? ) = 4/32 = 1/8 mol
n (H? ) = 2/2 = 1 mol
n (Total) = n (O? ) + n (H? ) = 1/8 + 1 = 9/8 mol
PV = nRT
P (Total) * 1 = (9/8) * 0.082 * 273
P (Total) = 25.18 atm
New answer posted
2 months agoContributor-Level 10
Λ°m (NaCl) = 126.45Scm² mol? ¹
Λ°m (HCl) = 426.16Scm² mol? ¹
Λ°m (CH? COONa) = 91Scm² mol? ¹
Λ°m (CH? COOH) =Λ°m (CH? COONa) +Λ°m (HCl)−Λ°m (NaCl)
= 91 + 426.16 – 126.45
= 391.72Scm² mol? ¹
New question posted
2 months agoNew answer posted
2 months agoContributor-Level 10
Both statements are correct independently but the reason is not the correct reason of the assertion.
New answer posted
2 months agoContributor-Level 9
Edge length in bcc, a? = 27 Å
Let, Edge length in fcc be a? Å
Now, the same element crystallises in bcc as well as fcc.
For bcc: 4r = √3 a? ⇒ r = (√3 / 4) a?
For fcc: 4r = √2 a? ⇒ r = a? / (2√2)
So, (√3 / 4) a? = a? / (2√2)
(√3 / 4) * 27 = a? / (2√2)
a? = 33.13 Å
The nearest integer is 33.
New answer posted
2 months agoContributor-Level 10
First, the number of unit cells in the given mass is determined. In an HCP structure, there are 6 atoms and 18 total voids (6 octahedral + 12 tetrahedral) per unit cell. Multiplying the number of unit cells by 18 gives the total number of voids. The result is14.9 x 10²¹, which is rounded.
New answer posted
2 months agoContributor-Level 9
Covalent solids have high melting point due to strong covalent bonds, also they are insulator in both solid as well as in molten state.
New answer posted
2 months agoContributor-Level 9
For an acidic buffer solution, pH = pKa + log ( [Base]/ [Acid]).
Given pH = 5.74 and pKa = 4.74.
5.74 = 4.74 + log ( [Base]/1).
1 = log ( [Base]).
[Base] = 10M.
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