Solid State

Get insights from 127 questions on Solid State, answered by students, alumni, and experts. You may also ask and answer any question you like about Solid State

Follow Ask Question
127

Questions

0

Discussions

4

Active Users

0

Followers

New answer posted

2 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

Please consider the following Image

 

New answer posted

2 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

For the dissociation of K? [Fe (CN)? ]? 4K? + [Fe (CN)? ]? , the number of ions produced (n) is 5.

The degree of dissociation (α) is related to the van't Hoff factor (i) by α = (i-1)/ (n-1).

Given α = 0.4: 0.4 = (i - 1) / (5 - 1) => 1.6 = I - 1 => I = 2.6

Using the depression in freezing point formula (ΔTf = i·Kf·m), and equating the ΔTf for two different solutions:
ΔTf (K? [Fe (CN)? ]) = ΔTf (A)
i? ·Kf·m? = i? ·Kf·m?
(2.6) * [ (18.1 / M) / (100-18.1)/1000] = (1) * [ (w? /M? ) / (W? /1000)]
The problem simplifies to finding the molar mass M of solute A:
2.6 * [18.1 / (M * 81.9)] * 1000 = [w? /M? ] * [1000/W? ]
Assuming the secon

...more

New answer posted

2 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

ρ = M/V
∴ 6.17 = (2 x MX? ) / (N? x (300 x 10? ¹? )³)
Solving MX? = 50 g
∴ No. of molecules in 200 g
= (200/50) x N? = 4 N?

New answer posted

2 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

In the ccp lattice of oxide ions effective number of O? ² ions = 8 *? + 6 * ½ = 4
In the ccp lattice,
No. of octahedral voids = 4
No. of tetrahedral voids = 8
Given M? atoms occupies 50% of octahedral voids and M? atoms occupies 12.5 of tetrahedral voids
No. of M? metal atoms = 4 *? /? = 2
No. of M? metal atoms = 8 * ¹²·? /? = 1
∴ Formula of the compound = (M? )? (M? )O?
∴ Oxidation states of metals M? & M? respectively are +2 and +4 .

New answer posted

2 months ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image 

 

New answer posted

2 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

AgBr=1.88g. Br=0.8g. %Br= (0.8/1.6)*100=50%.

New answer posted

2 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

For AB? compound possible geometry are

S. No.

Bond pair

Lone pair

Total

Hybridisation

Geometry

Polarity

1

4

0

4

Tetrahedral

non polar

2

4

1

5

Sea-saw

Polar

3

4

2

6

Square Planar

non polar

 

Square pyramidal can be polar due to lone pair moment as the bond pair moments will get cancelled out.

New answer posted

2 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

In FCC octahedral voids are present at the edge centers and body center


Consider a diagonal projected form edge centre passing through the body centre
Distance between octahedral voids = √2a/2 = a/√2

New answer posted

2 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

In Monoclinic crystal system, a ≠ b ≠ c and α = 90°, γ = 90° and β=120°.

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 678k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.