Some Basic Concepts of Chemistry
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Chlorophyll extracted form the crushed green leaves was dissolved in water to make 2 L solution of Mg of concentration 48 ppm. The number of atoms of Mg in this solution is x × 1020 atoms. The value of x is _____________. (Nearest Integer)
(Given : Atomic mass of Mg is 24 g mol-1; NA = 6.02 × 1023 mol-1)
Chlorophyll extracted form the crushed green leaves was dissolved in water to make 2 L solution of Mg of concentration 48 ppm. The number of atoms of Mg in this solution is x × 1020 atoms. The value of x is _____________. (Nearest Integer)
(Given : Atomic mass of Mg is 24 g mol-1; NA = 6.02 × 1023 mol-1)
Mass of solute = 48 * 2 * 10-3 gram
Atoms of Mg = 24.08 * 1020
A sample of 0.125g of an organic compound when analyzed by Duma’s method yields 22.78 mL of nitrogen gas collected over KOH solution at 280 K and 759 mm Hg. The percentage of nitrogen in the given organic compound is__________. (Nearest integer)
[Given: (a) The vapour pressure of water of 280K is 14.2mm Hg
(b) R = 0.082 L atm K-1 mol-1]
A sample of 0.125g of an organic compound when analyzed by Duma’s method yields 22.78 mL of nitrogen gas collected over KOH solution at 280 K and 759 mm Hg. The percentage of nitrogen in the given organic compound is__________. (Nearest integer)
[Given: (a) The vapour pressure of water of 280K is 14.2mm Hg
(b) R = 0.082 L atm K-1 mol-1]
2L of 0.2 M H2SO4 is reacted with 2L of 0.1 M NaOH solution, the molarity of the resulting product Na2SO4 in the solution is_________ millimolar (Nearest integer)
2L of 0.2 M H2SO4 is reacted with 2L of 0.1 M NaOH solution, the molarity of the resulting product Na2SO4 in the solution is_________ millimolar (Nearest integer)
H2SO4 + 2NaOH -> Na2SO4 + 2H2O
Number of mole = 0.2 × 2 2 × 0.1 &nb
The mass of ammonia in grams produced when of dinitrogen quantitatively reacts with of dihydrogen is(Mole Concept)
The mass of ammonia in grams produced when of dinitrogen quantitatively reacts with of dihydrogen is(Mole Concept)
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20g 5g
Consider the above reaction, the limiting reagent of the reaction and number of moles of NH3 formed respectively are:
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20g 5g
Consider the above reaction, the limiting reagent of the reaction and number of moles of NH3 formed respectively are:
t = 0 0
Here, N2 is the limiting reagent
and No of moles of NH3 = 2 × No of moles ofN2 reacted
116 g of a substance upon dissociation reaction yields 7.5 g of hydrogen 60 g of oxygen and 48.5 g of carbon. Given that the atomic masses of H, O and C are 1, 16 and 12, respectively. The data agrees with how many formulae of the following?
(a) CH3COOH (b) HCHO (c) CH3OOCH3 (d) CH3CHO
116 g of a substance upon dissociation reaction yields 7.5 g of hydrogen 60 g of oxygen and 48.5 g of carbon. Given that the atomic masses of H, O and C are 1, 16 and 12, respectively. The data agrees with how many formulae of the following?
(a) CH3COOH (b) HCHO (c) CH3OOCH3 (d) CH3CHO
Determining empirical formula of the given compound.
Mass &nbs
Assertion (A) : Combustion of 16 g of methane gives 18 g of water.
Reason (R) : In the combustion of methane, water is one of the products.
(i) Both A and R are true but R is not the correct explanation of A.
(ii) A is true but R is false.
(iii) A is false but R is true.
(iv) Both A and R are false.
Assertion (A) : Combustion of 16 g of methane gives 18 g of water.
Reason (R) : In the combustion of methane, water is one of the products.
(i) Both A and R are true but R is not the correct explanation of A.
(ii) A is true but R is false.
(iii) A is false but R is true.
(iv) Both A and R are false.
This is a Assertion and Reason Type Questions as classified in NCERT Exemplar
Option (C) The combustion reaction of methane is given below
CH4 + O2 -> CO2 + H2O
In this reaction, water and carbon dioxide are formed.
According to the reaction, 1 mole of methane gives 2 moles of water. So, 16 g of
Assertion (A) : Significant figures for 0.200 is 3 where as for 200 it is 1.
Reason (R) : Zero at the end or right of a number are significant provided they are not on the right side of the decimal point.
(i) Both A and R are true and R is correct explanation of A.
(ii) Both A and R are true but R is not a correct explanation of A.
(iii) A is true but R is false.
(iv) Both A and R are false.
Assertion (A) : Significant figures for 0.200 is 3 where as for 200 it is 1.
Reason (R) : Zero at the end or right of a number are significant provided they are not on the right side of the decimal point.
(i) Both A and R are true and R is correct explanation of A.
(ii) Both A and R are true but R is not a correct explanation of A.
(iii) A is true but R is false.
(iv) Both A and R are false.
This is a Assertion and Reason Type Questions as classified in NCERT Exemplar
Option (C)
In the decimal portion, only trailing or final zeros are significant. This is in accordance with the rules of significant figures.
The given number, 0.200 has 3 significant figures whereas the number, 200 has onl
Assertion (A) : One atomic mass unit is defined as one twelfth of the mass of one carbon-12 atom.
Reason (R) : Carbon-12 isotope is the most abundunt isotope of carbon and has been chosen as standard.
(i) Both A and R are true and R is the correct explanation of A.
(ii) Both A and R are true but R is not the correct explanation of A.
(iii) A is true but R is false.
(iv) Both A and R are false.
Assertion (A) : One atomic mass unit is defined as one twelfth of the mass of one carbon-12 atom.
Reason (R) : Carbon-12 isotope is the most abundunt isotope of carbon and has been chosen as standard.
(i) Both A and R are true and R is the correct explanation of A.
(ii) Both A and R are true but R is not the correct explanation of A.
(iii) A is true but R is false.
(iv) Both A and R are false.
This is a Assertion and Reason Type Questions as classified in NCERT Exemplar
Option (B)
Atomic mass unit is defined as a mass that is equal to accurately the mass of carbon-12 atom.
When scientists compare the relative atomic masses of the elements to the mass of carbon, they find that they are
In the following questions a statement of Assertion (A) followed by a statement of Reason (R) is given. Choose the correct option out of the choices given below each question.
Assertion (A): The empirical mass of ethene is half of its molecular mass.
Reason (R): The empirical formula represents the simplest whole number ratio of various atoms present in a compound.
(i) Both A and R are true and R is the correct explanation of A.
(ii) A is true but R is false.
(iii) A is false but R is true.
(iv) Both A and R are false
In the following questions a statement of Assertion (A) followed by a statement of Reason (R) is given. Choose the correct option out of the choices given below each question.
Assertion (A): The empirical mass of ethene is half of its molecular mass.
Reason (R): The empirical formula represents the simplest whole number ratio of various atoms present in a compound.
(i) Both A and R are true and R is the correct explanation of A.
(ii) A is true but R is false.
(iii) A is false but R is true.
(iv) Both A and R are false
This is a Assertion and Reason Type Questions as classified in NCERT Exemplar
(i) Both A and R are true and R is the correct explanation of A.
Explanation: The molecular formula gives the actual number of different atoms present in a molecule and the empirical formula gives a simple whole number rati