Some Basic Concepts of Chemistry
Get insights from 131 questions on Some Basic Concepts of Chemistry, answered by students, alumni, and experts. You may also ask and answer any question you like about Some Basic Concepts of Chemistry
- 131
Questions
- 0
Discussions
- 0
Active Users
- 0
Followers
Have a question about Some Basic Concepts of Chemistry? Ask our experts
Keep it short & simple. Type complete word. Avoid abusive language.
If two elements can combine to form more than one compound, the masses of one element that combine with a fixed mass of the other element, are in whole number ratio.
If two elements can combine to form more than one compound, the masses of one element that combine with a fixed mass of the other element, are in whole number ratio.
This is a Short Answer Type Questions as classified in NCERT Exemplar
(a) Is this statement true?
Ans: Yes the given statement is true
(b) If yes, according to which law?
Ans: Multiple law of proportions: According to the Law of Multiple proportions, when two elements combine to generate
45.4 L of dinitrogen reacted with 22.7 L of dioxygen and 45.4 L of nitrous oxide was formed. The reaction is given below:
2N2(g) + O2(g) → 2N2O(g)
Which law is being obeyed in this experiment? Write the statement of the law?
45.4 L of dinitrogen reacted with 22.7 L of dioxygen and 45.4 L of nitrous oxide was formed. The reaction is given below:
2N2(g) + O2(g) → 2N2O(g)
Which law is being obeyed in this experiment? Write the statement of the law?
This is a Short Answer Type Questions as classified in NCERT Exemplar
If all gases are at the same temperature and pressure, Gay lussac's law of gaseous volumes states that gases combine or are created in a chemical reaction in a simple volume ratio.
H2 (g) +
Calculate the mass percent of calcium, phosphorus and oxygen in calcium phosphate Ca3(PO4)2.
Calculate the mass percent of calcium, phosphorus and oxygen in calcium phosphate Ca3(PO4)2.
This is a Short Answer Type Questions as classified in NCERT Exemplar
Molecular mass of Ca3 (PO4)2 = 310.18 g / mole
Given mass of calcium 4 x 30= 120 g
Given mass of phosphorous = 31 x 2 =62 g
Given mass of oxygen = 16 x 8 = 128 g
Mass percent of Calcium = x 100 = 38.71%
Mass percent o
What is the difference between molality and molarity?
What is the difference between molality and molarity?
This is a Short Answer Type Questions as classified in NCERT Exemplar
The number of moles of a substance (known as the solute) dissolved in precisely 1 litce of a solution is known as molarity (solvent and solute combined). As a result, the formula for estimating molarity is as follows:
Molarity =
What is the symbol for SI unit of mole? How is the mole defined?
What is the symbol for SI unit of mole? How is the mole defined?
This is a Short Answer Type Questions as classified in NCERT Exemplar
SI unit of the mole is mol. The amount of a substance that contains as many particles or entities as there are atoms in exactly
12 g (0.012 kg) of the C-12 isotope is defined as a mole. One mole is defined as follows:
1 mole =&
How many significant figures should be present in the answer of the following calculations?
How many significant figures should be present in the answer of the following calculations?
This is a Short Answer Type Questions as classified in NCERT Exemplar
On solving the above equation, the result is 5.4. All non-zeroes digits are significant. The significant figure is 2.
What will be the mass of one atom of C-12 in grams?
What will be the mass of one atom of C-12 in grams?
This is a Short Answer Type Questions as classified in NCERT Exemplar
Mass of 1 mole of C-12 = 12g
1 mole contains 6.022×1023 atoms.
Thus, mass of 6.022×1023 atoms=12g
Mass of 1 atom of carbon =126.022×1023 g
&n
A box contains some identical red coloured balls, labelled as A, each weighing 2 grams. Another box contains identical blue coloured balls, labelled as B, each weighing 5 grams. Consider the combinations AB, AB2, A2B and A2B3 and show that law of multiple proportions is applicable.
A box contains some identical red coloured balls, labelled as A, each weighing 2 grams. Another box contains identical blue coloured balls, labelled as B, each weighing 5 grams. Consider the combinations AB, AB2, A2B and A2B3 and show that law of multiple proportions is applicable.
This is a Long Answer Type Questions as classified in NCERT Exemplar
In AB, 2 g of A combines with 5 g of B.
So, 4 g of A combines with 10 g of B.
In AB2, 2g of B combines with 10 g of B, So 4g of A combines with 20 g of B.
In A2B3 , 4G of B combines with 5 g of B.
In A2B3 4 g of B combined with 15 g
Define the law of multiple proportions. Explain it with two examples. How does this law point to the existance of atoms?
Define the law of multiple proportions. Explain it with two examples. How does this law point to the existance of atoms?
This is a Long Answer Type Questions as classified in NCERT Exemplar
According to the law of multiple proportions, when two elements react to form two or more than two chemical compounds, the ratio between different masses of one of the elements combining with a fixed mass of the other is always in t
Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the reaction given below:
CaCO3 (s) + 2HCl (aq) → CaCl2(aq) + CO2(g) + H2O(l)
What mass of CaCl2 will be formed when 250 mL of 0.76 M HCl reacts with 1000 g of CaCO3? Name the limiting reagent. Calculate the number of moles of CaCl2 formed in the reaction.
Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the reaction given below:
CaCO3 (s) + 2HCl (aq) → CaCl2(aq) + CO2(g) + H2O(l)
What mass of CaCl2 will be formed when 250 mL of 0.76 M HCl reacts with 1000 g of CaCO3? Name the limiting reagent. Calculate the number of moles of CaCl2 formed in the reaction.
This is a Long Answer Type Questions as classified in NCERT Exemplar
The volume of HCl solution is 250 mL and its molarity is 0.76M.
The number of moles of HCl as follows,
Moles of HCl Molarity Volume (in L)
= 0.76M 0.250 L
= 0.19 mol
The molar mass of CaCO3 is 100 g / gQl and the mass of CaCO3 is given