States of Matter

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New answer posted

4 months ago

0 Follower 8 Views

V
Vishal Baghel

Contributor-Level 10

F = -dU/dr = - [-12A/r¹³ + 6B/r? ]
F=0 ⇒ r= (2A/B)¹/?
U (at r= (2B/A)¹/? ) = -A²/4B

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

After removal A = 4  (12*2)=3

After removal B = 4 – 1 = 4 (only two atoms are removed)

Final formula of the compound = A3B4

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

Assuming ideal behaviour,  P=dRTM

P=100760atm, T=257+273=530K

d = 0.46gm/L

M=0.46*0.082*530100*760=151.93152g/mol

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

Xe = Xn

MeVe = MnVn

VeVn=MnMe1758.24

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

 xH2=nH2nH2+no2= (40/2) (40/2)+ (60/32) = 0.914

PH2=xH2*PT=0.914*2.22bar

New answer posted

5 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

PV = nmixRT

nmix=6*12.50.083*300? 3

Let moles of He is x

Moles of H2 = 3 – x

4x + 2 (3 – x) = 10

x = 2 mol

Mass of He = 8 gm

New answer posted

6 months ago

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V
Vishal Baghel

Contributor-Level 10

According to Heisenberg's uncertainly principle

Δx*Δp=h4π

Δv=6.63*10344*3.14*2*52.9*1012*9.1*1031

= 548273 ms-1

New answer posted

6 months ago

0 Follower 6 Views

P
Payal Gupta

Contributor-Level 10

For ideal gas using ;

PM = dRT

P = ( R T M ) d

Comparing with y = mx + C

Slope, m =  R T M

Slope  T

So; higher the slope higher the T

Hence, T3 > T2 > T1

New question posted

6 months ago

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New answer posted

8 months ago

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P
Payal Gupta

Contributor-Level 10

5.42. Dalton's law of partial pressure: When two or more non-reacting gases are enclosed in a vessel, the total pressure of the gaseous mixture is equal to the sum of the partial pressures that each gas will exert when enclosed separately in the same vessel at constant temperature.

P= P1 + P2 + P3

Where, P is the total pressure of the three gases A, B, and C enclosed in a container. P1, P2 and P3 are the partial pressures of the three gases when enclosed separately in the same vessel at a given temperature one by one.

No, the law cannot be applied. Carbon monoxide and oxygen readily combine to form carbon dioxide. The law can be appl

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