The S Block Elements
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10 months agoContributor-Level 10
(c) Reason is wrong a statement. More negative is the electrode potential, higher is the tendency of the element to lose electrons and hence, stronger is the reducing agent.
New answer posted
10 months agoContributor-Level 10
(b) Both the statements are correct but not the reason for the assertion.
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10 months agoNew answer posted
10 months agoContributor-Level 10
(d) The ionization enthalpies of the alkali metals are considerably low and decrease down the group from Li to Cs. This is because the effect of increasing size outweighs the increasing nuclear charge, and the outermost electron is very well screened from the nuclear charge.
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10 months agoNew question posted
10 months agoNew answer posted
10 months agoContributor-Level 10
(d) BaCO3
Thermal stability is directly proportional to the size of the cation i.e., larger the size of the atom, greater is its thermal stability. Ba being the biggest cation among the given compounds, has a greater thermal stability.
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10 months agoContributor-Level 10
(a) Li
Li+ is the smallest in size and thus, has the highest charge density and hence attracts the water molecules more strongly to form hydrated salts.
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10 months agoContributor-Level 10
(d) Cs
Size of Cs is the biggest thus, its melting point is the lowest, (d) is correct
New answer posted
10 months agoContributor-Level 10
(i) Lattice energy of BeO is comparatively higher than the hydration energy. Therefore, it is almost insoluble in water. Whereas, BeSO4 is ionic in nature and its hydration energy dominates the lattice energy.
(ii) Both BaO and BaSO4 are ionic compounds but the hydration energy of BaO is higher than the lattice energy therefore it is soluble in water.
(iii) Since the size of Li+ ion is very small in comparison to K+ ion, it polarises the electron cloud of I– ion to a great extent. Thus, Lil dissolves in ethanol more easily than the KI.
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