University Institute of Engineering and Technology, Kurukshetra University Eligibility
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3 months agoContributor-Level 10
For B.E./B.Tech at UIET Kurukshetra University, candidates must have passed 10+2 with Physics and Mathematics as compulsory subjects, and one from Chemistry/Biology/Biotechnology/Computer Science. A minimum of 45% aggregate marks (40% for SC/ST) in these subjects is required. Additionally, a valid JEE Main score and participation in HSTES centralized counseling are mandatory.
New answer posted
3 months agoContributor-Level 8
Admission to the B.E. / B.Tech courses at University Institute of Engineering and Technology (UIET), Kurukshetra University, primarily hinges on a candidate's performance in the JEE Main examination. Aspirants must first meet academic eligibility criteria, which typically include passing the 10+2 examination with at least 45% marks (40% for reserved categories) and having Physics and Mathematics as compulsory subjects, along with one of Chemistry, Biotechnology, Computer Science, Biology, Information Technology, or a Technical Vocational subject. Following a valid JEE Main score, admission is finalized through the centralized counselli
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a year agoBeginner-Level 1
Courses | Eligibility |
---|---|
B.E. / B.Tech | Candidate must have passed Diploma in Engineering/ Technology (relevant stream) with at least 45% marks in aggregate of all semesters (42.75% in case of SC students). Candidates who have completed B.Sc. in relevant field with at least 45% marks in aggregate (42.75% in case of SC students) with Physics and Math as a major subject are also eligible to apply. |
M.E./M.Tech | Candidates who have completed M.Sc. in Computer Science/ Information Technology/ Electronics or M.C.A. from a recognised UGC approved university/ institution with minimum 50% aggregate marks (minimum 47.5% aggregate marks for SC/ST candidates) can also apply. |
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