Work, Energy and Power

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New answer posted

a week ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

P = F v

= 18t4 – 18t2

->P (t = 2) =18 [16 − 4] = 216 W

New answer posted

a week ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

h2 = e2h1

h2 = h1/4

Energy loss =mgh1 - mgh2 /mgh1*100 = 75%

New answer posted

a week ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solutions

 

New answer posted

a week ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Height attained after first collision (h1) = e2h

h2e2h1e4h0

New answer posted

a week ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution 

 

New answer posted

a week ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

a week ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

2 weeks ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

m  =l0 kg

h= 5m

By work energy theorem

m g h = 1 2 m v 2

v 2 = 2 gh 

v = 2 g h

v = 1 0 0

v=10m/s

New answer posted

2 weeks ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Elastic potential energy stored in the spring

U = 1 2 k x 2

= 1 2 F x = F 2 2 k

H e n c e U 1 U 2 = k 2 k 1 F i s s a m e f o r b o t h s p r i n g s

= 500 1200 = 5 12

New answer posted

2 weeks ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

M=0.5kg

V=1.5m/s

K=50N/m

Maximum Compression of the spring

1 2 m v 2 = 1 2 k x 2

k x 2 = m v 2
x = v m k = 1 . 5 0 . 5 5 0 .

x=0.15m

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