Work, Energy and Power

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New answer posted

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

  v 2 2 a = s (a = mg)

v2 = 2 * mgs

v2 = 2 * (0.4) * 10 * 10

v2 = 80

Wf = Dk

= 1 2 * 1 0 0 * 8 0  

Wf = – 4000

New answer posted

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

By conservation of mechanical energy

mg (1) =  1 2 mv2 + mg (0.5)

v2 = 10

v =  1 0 m/s

New answer posted

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

P = F v

= 18t4 – 18t2

->P (t = 2) =18 [16 − 4] = 216 W

New answer posted

a month ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

h2 = e2h1

h2 = h1/4

Energy loss =mgh1 - mgh2 /mgh1*100 = 75%

New answer posted

a month ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solutions

 

New answer posted

a month ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Height attained after first collision (h1) = e2h

h2e2h1e4h0

New answer posted

a month ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution 

 

New answer posted

a month ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

a month ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

2 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

m  =l0 kg

h= 5m

By work energy theorem

m g h = 1 2 m v 2

v 2 = 2 gh 

v = 2 g h

v = 1 0 0

v=10m/s

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