Work, Energy and Power

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New answer posted

7 months ago

0 Follower 19 Views

A
alok kumar singh

Contributor-Level 10

ΔE = have = 13.6Z² (1/n? ² - 1/n? ²)eV.
hv = 13.6 (1²) (1/n² - 1/ (n+1)²) = 13.6 (n+1)²-n²)/ (n² (n+1)²)
v = (13.6/h) * (2n+1)/ (n² (n+1)²). For n>>1, v ≈ (13.6/h) (2n/n? ) ∝ 1/n³.

New answer posted

7 months ago

0 Follower 12 Views

V
Vishal Baghel

Contributor-Level 10

Let AC = l, BC = 2l, AB = 3l
Apply work-Energy theorem
W? + W? = ΔKE
Mg (3l)sinθ - µmgcosθ (l) = 0+0
µmgcosθl = 3mglsinθ


µ=3tanθ = ktanθ
∴ k=3

New answer posted

7 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

P = constant


m (dv/dt) = P
∫? vdv = P/m ∫? dt
v²/2 = Pt/m ⇒ v = (2Pt/m)¹/²
dx/dt = √ (2P/m) t¹/²
∫? dx = √ (2P/m) ∫? t¹/² dt
x = √ (2P/m) (t³/² / (3/2) = √ (2P/m) * (2/3) * t³/²
= (2/3) * 27 = 18

New answer posted

7 months ago

0 Follower 5 Views

R
Raj Pandey

Contributor-Level 9

For elastic collision   K E i = K E r

1 2 m * 25 + 1 2 * m * 9 = 1 2 m * 32 + 1 2 m v 2

34 = 32 + v 2

K E = 1 2 * 0.1 * 2 = 0.1 J = 1 10

x = 1

New answer posted

7 months ago

0 Follower 9 Views

V
Vishal Baghel

Contributor-Level 10

E ? = 9 s i n ? 1.6 * 10 3 x + 48 * 10 10 t k ˆ ? / m

4000 * V + m g * V = P

60 * 746 2000 * 4000 = V V = 1.86 m / s 1.9 m / s

New answer posted

7 months ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

m ? 2 ( l + x ) = k x

l x + 1 = k m ? 2 x = l m ? 2 k - m ? 2

 

New answer posted

7 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

New answer posted

7 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Using conservation of linear momentum, we can write
P? = P? ⇒ mv = (M+m)V
Using conservation of Mechanical energy, we can write
½ (M+m)V² = (M+m)gh ⇒ V = √2gh
⇒ v = (M+m)/m)√2gh
= (6/0.01)√ (2*9.8*0.098) = 600 * 1.386 = 831.4 m/s

New answer posted

7 months ago

0 Follower 12 Views

V
Vishal Baghel

Contributor-Level 10

v = ∫a dt = (1/M)∫F dt
v = (F? /M) ∫ [1 - (t-T)²/T²] dt from 0 to 2T
= (F? /M) [t - (t-T)³/3T²]? ²?
= (F? /M) [ (2T - T³/3T²) - (0 - (-T)³/3T²) ]
= (F? /M) [ 2T - T/3 - T/3 ] = (F? /M) [ 4T/3 ] = 4F? T/3M.

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