Chemistry Electrochemistry
Get insights from 102 questions on Chemistry Electrochemistry, answered by students, alumni, and experts. You may also ask and answer any question you like about Chemistry Electrochemistry
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New answer posted
2 months agoContributor-Level 10
E°cell = E°cathode - E°anode = (+1.510) - (1.229) = +0.287 V. As E°cell is positive the cell will work.
New answer posted
2 months agoContributor-Level 10
First, the specific conductance (κ) is calculated (κ = conductance * cell constant), and units are converted. Then, the molar conductivity (Λ? ) is found using the formula Λ? = κ / Concentration, with all units in the SI system. The calculation yields 14.3 mS m² mol? ¹.
Answer: 14 (Rounded off)
New answer posted
2 months agoContributor-Level 9
λ° (BaCl? ) = 280 Scm²mol? ¹
λ° (H? SO? ) = 860 Scm²mol? ¹
λ° (HCl) = 426 Scm²mol? ¹
λ° (BaSO? ) = λ° (BaCl? ) + λ° (H? SO? ) - 2λ° (HCl)
= 280 + 860 - 2 * 426
= 288 Scm² mol? ¹
New answer posted
2 months agoContributor-Level 9
For the complex K? [Cr (oxalate)? ], the central metal ion is Cr³?
Electronic configuration of Cr (24) is [Ar] 4s¹3d?
Electronic configuration of Cr³? is [Ar] 4s?3d³.
The number of unpaired electrons in Cr³? is 3.
New answer posted
2 months agoContributor-Level 10
The reaction shown is:
Anisole diazonium chloride (A) + Ethanol → Anisole + Acetaldehyde (X) + HCl + N? (Y)
New answer posted
2 months agoContributor-Level 10
The reactions in the Solvay process are:
NaCl + H? O + NH? + CO? → NH? Cl + NaHCO?
2NaHCO? → Na? CO? + CO? + H? O
2NH? Cl + Ca (OH)? → CaCl? + 2NH? + H? O
CaCl? is a byproduct of the process.
New answer posted
2 months agoContributor-Level 9
Matching Calcium Compounds to their Description:
o Ca (OCl)? : Bleach
o CaSO? • ½ H? O: Plaster of paris
o CaO: Component of cement
o CaCO? : Antacid
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
 - 1.2k Exams
 - 682k Reviews
 - 1800k Answers
 




