Chemistry Electrochemistry

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V
Vishal Baghel

Contributor-Level 10

Silver will not be able to reduce Cu²? to Cu.

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V
Vishal Baghel

Contributor-Level 10

cell = E°cathode - E°anode = (+1.510) - (1.229) = +0.287 V. As E°cell is positive the cell will work.

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2 months ago

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A
alok kumar singh

Contributor-Level 10

First, the specific conductance (κ) is calculated (κ = conductance * cell constant), and units are converted. Then, the molar conductivity (Λ? ) is found using the formula Λ? = κ / Concentration, with all units in the SI system. The calculation yields 14.3 mS m² mol? ¹.
Answer: 14 (Rounded off)

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2 months ago

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R
Raj Pandey

Contributor-Level 9

λ° (BaCl? ) = 280 Scm²mol? ¹
λ° (H? SO? ) = 860 Scm²mol? ¹
λ° (HCl) = 426 Scm²mol? ¹
λ° (BaSO? ) = λ° (BaCl? ) + λ° (H? SO? ) - 2λ° (HCl)
= 280 + 860 - 2 * 426
= 288 Scm² mol? ¹

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R
Raj Pandey

Contributor-Level 9

For the complex K? [Cr (oxalate)? ], the central metal ion is Cr³?

Electronic configuration of Cr (24) is [Ar] 4s¹3d?

Electronic configuration of Cr³? is [Ar] 4s?3d³.

The number of unpaired electrons in Cr³? is 3.

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R
Raj Pandey

Contributor-Level 9

Please consider the following Image

 

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R
Raj Pandey

Contributor-Level 9

Benzyl amine (0.1 mole) reacts with 3 equivalents of CH? Br to form Benzyl trimethyl ammonium bromide.

Given 23g of Benzyl trimethyl ammonium bromide (molar mass 230 g/mol ), which is 0.1 mol.

Therefore, moles of CH? Br = 0.3 = 3 x 10? ¹. The value of n is 3.

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2 months ago

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A
alok kumar singh

Contributor-Level 10

The reaction shown is:
Anisole diazonium chloride (A) + Ethanol → Anisole + Acetaldehyde (X) + HCl + N? (Y)

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A
alok kumar singh

Contributor-Level 10

The reactions in the Solvay process are:

NaCl + H? O + NH? + CO? → NH? Cl + NaHCO?

2NaHCO? → Na? CO? + CO? + H? O

2NH? Cl + Ca (OH)? → CaCl? + 2NH? + H? O

CaCl? is a byproduct of the process.

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R
Raj Pandey

Contributor-Level 9

Matching Calcium Compounds to their Description:

o   Ca (OCl)? : Bleach

o   CaSO? • ½ H? O: Plaster of paris

o   CaO: Component of cement

o   CaCO? : Antacid

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