Chemistry NCERT Exemplar Solutions Class 11th Chapter Thirteen
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New answer posted
4 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
It is a Wurtz reaction where alkane is formed.
New answer posted
4 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
The structure of 2-methylbutane is
2-methylbutane
Total number | Total amount of monochlorinated Product | % of monochlorinated product | |
1° | 9 | 9 | 41.7 |
2° | 2 | 7.6 | 35.2 |
3° | 1 | 5 | 23.1 |
New answer posted
4 months ago
Contributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
Electrophiles | Nucleophiles |
(iii), (iv), (v) | (i), (ii), (vi), (vii), (viii) |
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4 months ago
Contributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
In presence of (Ph-CO-O)2it lead to CH3-CH2-CH2Br as the reaction undergo by free radical mechanism
However in absence of (Ph-CO-O)2 the reaction undergo by carbocation intermediate thus lead to give CH3-CHBr-CH3
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4 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
New answer posted
4 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
The nitro group strongly deactivate the benzene towards the electrophilic substitution reaction due to the -R and -I effect
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4 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
Due to the +R effect halogens are ortho and para directing groups.
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4 months ago
Contributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
The electron donating group increases the reactivity in electrophilic substitution reaction whereas the electron withdrawing group decreases the reactivity in electrophilic substitution.
Thus, the order of reactivity
New answer posted
4 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
New answer posted
4 months ago
Contributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
The benzene here would undergo Friedel-Crafts alkylation reaction where carbocation is formed as an intermediate, thus secondary carbocation is formed as an intermediate due to its greater stability than that of the primary carbocation.
The final product obtained is
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