Chemistry

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New answer posted

8 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Kindly go through the solution

(a)

New answer posted

8 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

Kindly go through the solution

(a)

New question posted

8 months ago

0 Follower 2 Views

New question posted

8 months ago

0 Follower 2 Views

New answer posted

8 months ago

0 Follower 28 Views

V
Vishal Baghel

Contributor-Level 10

Kindly go through the solution

New answer posted

8 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

eq of H2O2= eq of KMnO4

=0.316158*5=0.01=0.01*170.2*100=85%

New answer posted

8 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

New answer posted

8 months ago

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A
alok kumar singh

Contributor-Level 10

N2+3H2? 2NH3

2.8*103281*10320.1*103molLR0.5*103mol

 Mass of NH3 produced =0.2*103*17=3.4kg=3400g

New answer posted

8 months ago

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A
alok kumar singh

Contributor-Level 10

Sol. first order reaction

K=2.303tlog? a0a0-x

K=2.30390log? a00.25a0

=0.0154

t=60%=2.303Klog? a0a0. (2)=2.3030.0154* (1-0.602)=59.51mins60

New answer posted

8 months ago

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A
alok kumar singh

Contributor-Level 10

Sol. 

PT=XAPA0-PB0+PB0

ATQ

550=14PA0-PB0+PB0

2200=PA0-PB0+4PB0

560=15PA0-PB0+PB0

2200=PA0-PB0+5PB0

PA0+3PB0=2200

PA0±4PB0=2800PB0=600

PA0=400mmHg

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