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Chemistry Chemistry NCERT Exemplar Solutions Class 12th Chapter Thirteen

In bromination of Propyne, with Bromine 1, 1, 2, 2-tetrabromopropane is obtained in 27% yield. The amount of 1, 1, 2, 2- tetrabromopropane obtained from 1g of Bromine in this reaction is_______________* 10^-¹g. (Nearest integer) (Molar mass: Bromine = 80g / mol)

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Vishal Baghel

Contributor-Level 10

Reaction is

Mass of product, 1, 2, 2- tetrobromopropane obtained

= $\frac{1 * 360}{160 * 2} * \frac{27}{100}$

= 3.30375

= 3.0375 * 10^-1

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Chemistry Chemistry NCERT Exemplar Solutions Class 12th Chapter Fifteen

In a linear tetrapeptide (Constituted with different amino acids), (number of amino acids) (number of peptide bonds) is_______________.

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Vishal Baghel

Contributor-Level 10

No. of Amino acid units are 4 and

No. of peptide bonds are 3

In tetrapeptide

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Chemistry Chemistry NCERT Exemplar Solutions Class 12th Chapter Four

The reaction between X and Y is first order respect to X and zero order with respect to Y.

Examine the data of table and calculate ratio of numerical values of M and L (Nearest integer)

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Vishal Baghel

Contributor-Level 10

According to condition

Rate $\propto {[X]}^{1} {[Y]}^{0}$

By using experimental data I and II

$\frac{4 * 1 0^{- 3}}{2 * 1 0^{- 3}} = \frac{L}{0.1} ∴ L = 0.2$

And by using experimental data I and II

$\frac{M * 1 0^{- 3}}{2 * 1 0^{- 3}} = \frac{0.4}{0.1}$

$∴$ M = 8

Ratio of $(\frac{M}{L}) = \frac{8}{0.2} = 40$

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Chemistry Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven

If the solubility product of PbS is 8 * 10^-²⁸, then the solubility of PbS in pure water at 298 K is $x * 1 0^{- 16} m o l L^{- 1} .$ The value of x is__________. (Nearest integer)

[Given: $\sqrt[]{2} = 1.41]$

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Vishal Baghel

Contributor-Level 10

$S = \sqrt[]{K s p} = \sqrt[]{8 * 1 0^{- 28}} = 2.82 * 1 0^{- 14}$

Or solubility of PbS = 282 * 10^-16

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Chemistry Chemistry NCERT Exemplar Solutions Class 12th Chapter Two

If O₂ gas is bubbled through water at 303 K, the number of millimoles of O₂ gas that dissolve in 1 litre of water is______________. (Nearest integer)

(Given: Henry's Law constant for O₂ at 303 K is 46.82 k bar and partial pressure of O₂ = 0.920 bar)

(Assume solubility of O₂ in water in too small, nearly negligible)

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Vishal Baghel

Contributor-Level 10

According to Henry's law

P = K_H * mole fraction of solute

$0.92 = 46.82 * 1000 * \frac{m o l o f O_{2}}{55.5}$

$∴$ Mole of O₂ = 1.09 * 10^-3

$∴ M i l l i m o l e = 1.09 \approx 1$

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Chemistry Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven

When 600 mL of 0.2 M HNO₃ is mixed with 400 mL of 0.1 M NaOH solution in a flask, the rise in temperature of the flask is_________ * 10^-² °C.

(Enthalpy of neutralization = 57 kJ mol^-¹ and Specific heat of water = 4.2 JK^-¹ g^-¹)

(Neglect heat capacity of flask)

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Vishal Baghel

Contributor-Level 10

HNO₃ + NaOH ® NaNO₃ + H₂O

t = 0, (600 * 0.2)_meq (400 * 0.1)_meq 40 meq 40 meq

120 meq 40 meq

t = $\infty$ 80 meq -

Total heat

...more

HNO₃ + NaOH ® NaNO₃ + H₂O

t = 0, (600 * 0.2)_meq (400 * 0.1)_meq 40 meq 40 meq

120 meq 40 meq

t = $\infty$ 80 meq -

Total heat produced during neutralization ;

$= \frac{40}{1000} * 57 * 1000 J = 2280 J = m . s θ$

2280 = 1000 * 4.2 * q

$∴ θ = 2280 / 4200 = 54.28 * 1 0^{- 2} C$

less

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a year ago

Chemistry Chemistry NCERT Exemplar Solutions Class 12th Chapter Five

The minimum uncertainty in the speed of an electron in an one dimensional region of length 2a₀ (Where a₀ = Bohr radius 52.9 pm) is__________ km s^-¹.

(Given: Mass of electron = 9.1 * 10^-³¹ kg, Planck's constant h = 6.63 * 10^-³⁴ Js)

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Vishal Baghel

Contributor-Level 10

According to Heisenberg's uncertainly principle

$Δ x * Δ p = \frac{h}{4 π}$

$∴ Δ v = \frac{6.63 * 1 0^{- 34}}{4 * 3.14 * 2 * 52.9 * 1 0^{- 12} * 9.1 * 1 0^{- 31}}$

= 548273 ms^-1

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a year ago

Chemistry Chemistry NCERT Exemplar Solutions Class 12th Chapter One

Ionic radii of cation A+ and anion B are 102 and 181 pm respectively. These ions are allowed to crystallize into an ionic solid. This crystal has cubic close packing for B. A+ is present in all octahedral voids. The edge length of the unit cell of the crystal AB is________ pm.

(Nearest integer)

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Vishal Baghel

Contributor-Level 10

Edge length of the unit cell AB = a = 2 $(r_{+} + r_{-})$

$∴ a = 2 (102 + 181) = 2 (283) = 566$

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a year ago

Chemistry Chemistry NCERT Exemplar Solutions Class 12th Chapter Three

Resistance of a conductivity cell (cell constant 129 m1) filled with 74.5 ppm solution of KCl is $100 Ω$ (labeled as solution 1). When the same cell is filled with KCl solution of 149 ppm, the resistance is $50 Ω$ (labeled as solution 2). The ratio of molar conductivity of solution 1 and solution 2 is i.e. $\frac{\land_{1}}{\land_{2}} = x * 1 0^{- 3} .$ The value of x is________. (Nearest integer)

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Vishal Baghel

Contributor-Level 10

Given cell constant $\frac{l}{A} = 129 m^{- 1}$

Ratio of ppm of two solution of KCl = Ratio of moles of per unit volume.

$\frac{{(p p m)}_{K C l_{1}}}{{(p p m)}_{K C l_{2}}} = \frac{M_{1}}{M_{2}} = \frac{74.5}{149.0} = \frac{1}{2}$

$∴ \frac{\land_{1}}{\land_{2}} = 1000 * 1 0^{- 3}$

$∴$ x = 1000

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a year ago

Chemistry Chemistry NCERT Exemplar Solutions Class 12th Chapter Sixteen

Which of the following compounds is an example of hypnotic drug?

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Vishal Baghel

Contributor-Level 10

Drug used in the treatment of sleeping problems

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