Class 11th
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New answer posted
2 months ago
Contributor-Level 10
B is least basic as lone pair of electron is present in resonance so as to make the system aromatic in nature
D is most basic as it results in formation of equivalent resonating structures upon attack of H?
Among A and C, the former is less basic as sp² hybridistion of nitrogen decrease its basic strength.
Hence option 3 follows
New answer posted
2 months agoContributor-Level 10
f = f_Translational + f_Rotational + f_Vibrational
f = 3 + 3 + 48 = 54 (Since each vibrational mode has two degrees of freedom)
γ = 1 + 2/f = 1 + 2/54 = 1 + 1/27 = 28/27 ≈ 1.03
New answer posted
2 months agoContributor-Level 10
According to Aufbau's principal, the increasing energy of atomic orbitals for sixth period element follows the order
6s < 4f < 5d < 6p
New question posted
2 months agoNew answer posted
2 months ago
Contributor-Level 10
N = mg - F_L
f_s = mv²/R ≤ μsN = μs (mg - F_L)
F_L = m (v²/μsR - g)
New answer posted
2 months agoContributor-Level 10
K? = ½ mv² + ½ Iω²
Since I =? mr² and v=rω,
K? = ½ mv² + ½ (? mr²) (v/r)² = ½ mv² +? mv² = (7/10)mv² = 140 J
K_f = 0.05 K?
(7/10)mv_f² = 0.05 * (140)
(7/10)mv_f² = 7
v_f² = 20
v_f = √20 ≈ 4.47 m/s
New answer posted
2 months agoContributor-Level 10
t? + t? = t
v? /t? = α and v? /t? = β
t? = v? /α and t? = v? /β
v? /α + v? /β = t
v? (1/α + 1/β) = t
v? = (αβt) / (α + β)
Distance traveled = Area under speed-time graph
Distance = ½ * base * height = ½ * t * v?
Distance = ½ * t * (αβt) / (α + β) = (αβt²) / (2 (α + β)
New answer posted
2 months ago
Contributor-Level 10
Position vector about O (r_o) = 5i + 5√3j
Force vector (F) = 4i - 3j
Torque about O (τ_o) = r_o * F
τ_o = (5i + 5√3j) * (4i - 3j)
τ_o = -15k - 20√3k = (-15 - 20√3)k
Position vector about Q (r_q) = -5i + 5√3j
Torque about Q (τ_q) = r_q * F
τ_q = (-5i + 5√3j) * (4i - 3j)
τ_q = 15k - 20√3k = (15 - 20√3)k
New answer posted
2 months agoContributor-Level 10
Positive zero error = 0.02 cm
Reading = 8.5 + 6 * 0.01 = 8.56 cm
Actual reading = Reading - Positive zero error
Actual reading = 8.56 - 0.02 = 8.54 cm
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