Class 11th
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2 months agoContributor-Level 10
For an elastic collision where C comes to rest, and the compression in the spring is maximum, the velocities of A and B are equal (v). Using the conservation of mechanical energy:
(1/2)mv? ² = 2 * (1/2)mv² + (1/2)kx²
This gives the maximum compression x as:
x = v? * √* (m / 2k)*
New answer posted
2 months agoContributor-Level 10
In an aqueous medium, all alkali metal cations are converted into their hydrated form. More intensely positive cations have more hydration, and hence the size of the cation increases after hydration. Therefore, the Li? cation has a larger size in hydrated form and the least conductivity. The order of conductivity of alkali metal ions is: Li? < Na? < K? < Rb? < Cs?
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2 months agoContributor-Level 9
For constant acceleration, a,
x = ut + (1/2)at² ⇒ x-t graph is parabola.
v = u + at ⇒ v-t graph is straight line with positive slope.
New answer posted
2 months agoContributor-Level 10
Except for option (D), all are the important characteristics of D? O. D? O is useful for the isotopic leveling effect in reaction mechanisms. The dielectric constants of H? O and D? O are respectively 80 and 60.
New answer posted
2 months agoContributor-Level 10
Due to the larger size of the Cl-atom, the addition of an electron in the outermost orbit produces less electronic repulsion with respect to the F-atom. The following are the electron gain enthalpies in (KJ) of halogens:
F → -328, Cl → -349, Br → -325, I → -295
New answer posted
2 months agoContributor-Level 9
Layers of atmosphere are in order of (from bottom) troposphere, stratosphere, mesosphere, thermosphere.
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2 months agoContributor-Level 9
For adiabatic process CD,
W = (P? V? - P? V? ) / (γ - 1) = (100 * 4 - 200 * 3) / (1.4 - 1) = -500J
New answer posted
2 months agoContributor-Level 10
A central atom having two lone pairs and three bond pairs reflects sp³d hybridization and a corresponding T-shaped geometry.
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2 months agoNew answer posted
2 months agoBeginner-Level 5
As you know, electrovalent bonds result very strong electrostatic attraction force. All the factors that help maximize this electrostatic attraction are important for the formation of the ionic bond. Here are the important factors;
- Low ionization energy Metal
- High electron affinity Non Metal
- Large-sized cations
- Small-sized anions
- Electronegativity equal to or greater than 1.7
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