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2 months ago

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A
alok kumar singh

Contributor-Level 10

With decrease in inter-nuclear distance, the potential energy of the system decreases, reaches a minimum value and then sharply increases due to rise in inter-electronic as well as inter-nuclear repulsions

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

The number of revolutions can be found using the rotational kinematic equation for angular displacement (θ):
θ = (ω_initial + ω_final)/2 * t
Number of revolutions = θ / 2π
Number of revolutions = [ (ω_final + ω_initial) * t] / (2 * 2π)

Based on the numerical values provided in the document, the calculation is:
Number of revolution = [ (2π * 3360/60 + 0) * t] / (2 * 2π) . with further calculation yielding the result:
Number of revolution = 728

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

The equations for an object rolling down an inclined plane without slipping are:

·       Force equation: mg sinθ - f_s = ma

·       Torque equation: f_s R = Iα

Since a = αR, we can write f_s = Iα/R = Ia/R².
Substituting this into the force equation:
mg sinθ - Ia/R² = ma
mg sinθ = a (m + I/R²)
a = (mg sinθ) / (m + I/R²)

The time taken to travel a distance S is given by S = ½ at², which means t ∝ 1/√a. Therefore, the object with the largest acceleration (a) will arrive first.

The problem is analyzed for different bodies:

·       Ring: I =

...more

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

R_eq = R? + R?

L_total / (K_eq * A) = L? / (K? A) + L? / (K? A)
Assuming L? = L? = l, L_total = 2l

2l / (K_eq * A) = l/ (K? A) + l/ (K? A)

2/K_eq = 1/K? + 1/K? = (K? + K? )/ (K? )

K_eq = 2K? K? / (K? + K? )

New answer posted

2 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

In water gas shift reaction carbon monoxide is oxidized into carbon dioxide by treating it with steam in presence of catalyst.

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

U = U? + U? = (n? /N_A) (F? R/2)T? + (n? /N_A) (F? R/2)T?

For the mixture: U = (n? +n? )/N_A * (FR/2)T

F = (n? F? + n? F? ) / (n? + n? )

Equating the expressions for U and solving for T gives:
T = (n? F? T? + n? F? T? ) / (n? F? + n? F? )

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

K = U

½ mω² (A² - x²) = ½ mω²x²

A² - x² = x²

A² = 2x²

x = ± A/√2

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

P? - P? = 4T/a

P? - P? = 4T/b

P? - P? = 4T (1/a - 1/b)

Also, P? - P? = 4T/r

4T/r = 4T (1/a - 1/b)

1/r = (b-a)/ab

r = ab / (b-a)

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

η = 1 - T_C / T_H

η = 1 - 400/800 = 1 - ½ = ½

η = W/Q_H ⇒ ½ = W/Q_H ⇒ Q_H = 2W = 2 * 1200 = 2400 J

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