Class 11th

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New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Cross product will represent a vector perpendicular to both the vector.

Dir. Of Motion of P : = ( i ^ + j ^ ) * ( j ^ * k ^ )

= k ^ j ^ + i ^

Dir. Of Motion of Q = ( i ^ + j ^ ) * ( i ^ + j ^ )

= 2 k ^

c o s θ = a . b a b = 2 2 3 = 1 3 θ = c o s 1 ( 1 3 )

New answer posted

3 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

Energy density (u) = 1 2 * σ * ε = 1 2 * Y ε * ε = 1 2 ε 2 Y

e n e r g y s t o r e d / m 2 = 1 2 ε 2 Y A

Strain ( ε ) = Δ l l 0 = α Δ T = 1 0 5 * 1 0 = 1 0 4

e n e r g y s t o r e d / m 2 = 1 2 * 1 0 8 * 1 0 1 1 * 1 0 2 = 5

New answer posted

3 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

E 1 : x 2 a 2 + y 2 b 2 = 1

  e 1 2 = 1 b 2 a 2 -(i)

Let E 2 : x 2 a 2 + y 2 B 2 = 1  

B > a

  e 2 2 = 1 a 2 B 2 a n d g i v e n B e 2 = b

e 2 = 3 5 2 = ( 5 1 2 ) 2

e = 5 1 2

New answer posted

3 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

T = 2 π l g

g = 4 π 2 l T 2

Δ g g = Δ l l + 2 Δ T T

Student 1 will get least error because it has more number of oscillation

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

V P = V 0 2 + V 0 2 = 2 V 0

New question posted

3 months ago

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New answer posted

3 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

Using conservation of energy:

m g h = 1 2 l c m ω 2 + 1 2 m v 2 = 1 2 l c m V 2 r 2 + 1 2 m v 2

v 2 = m g h 1 2 l c m r 2 + m v 2

So, sphere has the greatest velocity of COM and ring has least.

New answer posted

3 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Total energy of monoatomic gas at equilibrium

= 3 2 K B T

New answer posted

3 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

x (t) = A sin ω  t + B cos ω t

x ( t ) = A 2 + B 2 s i n ( ω t + δ ) = A 2 + B 2 c o s ( ω t ( π 2 δ ) )

At t = 0:

x ( 0 ) = A 2 + B 2 s i n ( δ )

v ( 0 ) = ω A 2 + B 2 c o s ( δ )

( x ( 0 ) ) 2 + ( v ( 0 ) ω ) 2 = A 2 + B 2

t a n ? = t a n ( π 2 δ ) = c o t δ = v ( 0 ) x ( 0 ) ω

? = t a n 1 ( v ( 0 ) x ( 0 ) ω )

New answer posted

3 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

s i n 7 x = c o s 7 x = 1 , x [ 0 , 4 π ]            

will satisfy for sin x = 1, cos x = 0

x = π 2 & 5 π 2 .              

or, cos x = 1, sin x = 0

x = 0, 2π, 4π              total 5 solutions

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