Class 11th

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New answer posted

3 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Com (Conservation of Momentum)

Pi = Pf

m u 1 + 5 m u 2 = m v 1 + 5 m v 2

m u 1 = m v 1 + 5 m v 2

u 1 + v 1 + 5 v 2  …….(i)

& e = 1 = v 2 v 1 U 1 U 2 = v 2 v 1 u 1

  u 1 = v 2 v 1 …….(ii)

Equation (i) + (ii)

k . E T = 5 9 ( K . E ) i = 5 5 . 6 %

 

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

The law of gravitation holds good for any pair of bodies in the universe.

This is correct statement.

The weight of any person becomes zero when the person is at the centre of the Earth.

Weight = mg

= m * 0 [g = 0 at the centre of the Earth]

= 0

New answer posted

3 months ago

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A
alok kumar singh

Contributor-Level 10

V r m s > V a v > V m p

New answer posted

3 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

To keep,   Δ α c m = 0

     

      M 1 Δ x 1 + M 2 Δ X 2 = 0          

1 0 * 6 + 3 0 Δ X 2 = 0      

Δ X 2 = 1 0 * 6 3 0

Δ X 2 = 2 c m        

i.e. 2 cm towards the 10 kg block.

New answer posted

3 months ago

0 Follower 9 Views

V
Vishal Baghel

Contributor-Level 10

Assume both the block is moving with common acceleration 'a' then

a = F m + M . . . . . . . ( i )

N = mg

N = 2g

f = m a = m F m + M

For no slipping

2 F 1 0 g

F 5 g

F 5 * 9 . 8 F 4 9 . 0 N

New answer posted

3 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

C l > F   (exception)

S > Se (size effect)

L i > N a   (size effect)

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Given, m = 0.6 ±  0.006

p = m v = m π r 2 l

Δ ρ ρ * 1 0 0 = Δ m m * 1 0 0 + 2 Δ r r * 1 0 0 + Δ l l * 1 0 0

= 1 + 2 * 1 + 1

New answer posted

3 months ago

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A
alok kumar singh

Contributor-Level 10

N 2 + O 2 ? 2 N O

Oxidation state changes

New answer posted

3 months ago

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C
Chandra Pruthi

Beginner-Level 5

You can check the below given table for the comarative differences between valence bond theory and molecular orbital theory.

FeatureValence Bond Theory (VBT)Molecular Orbital Theory (MOT)
Basic ConceptOverlap of atomic orbitals.Atomic orbitals combine to form molecular orbitals
Bond FormationDue to head-on (? ) or sideways (? ) overlap of atomic orbitals.Linear combination of atomic orbitals (LCAO) to form bonding and antibonding MOs.
Explanation of Magnetic BehaviorOften fails to explain magnetism of molecules (e.g., O? is paramagnetic).Accurately explains paramagnetism/diamagnetism (O? is paramagnetic due to unpaired electrons in antibonding orbitals).
Bond Order Not clearly defined.Bond order = ½ (No. of bonding electrons - No. of antibonding electrons)
Electron DelocalizationElectrons are localized between two atoms.Electrons may be delocalized over multiple atoms.
Energy ConsiderationConsiders only overlapping orbitals and their energy.Considers combination and energy differences of atomic orbitals.
ApplicabilityWorks well for simple molecules like H? , HF, etc.Better for explaining molecules like O? , N? , and ions like NO? , CN?

New answer posted

3 months ago

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S
Syed Aquib Ur Rahman

Contributor-Level 10

From the physics perspective, in uniform circular motion, speed and angular velocity are constant. That makes the angular acceleration and tangential acceleration are zero. Non-uniform motion, on the other hand, has varying speed and angular velocity, where angular acceleration is non-zero. 

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