Class 11th

A 42.12% (w/v) solution of NaCl causes precipitation of a certain sol in 10 hours. The coagulating value of NaCl for the sol is

[Given molar mass : Na = 23.0g mol^-¹; Cl = 35.5g mol^-¹]

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Class 11th Chemistry Chemical Bonding and Molecular Structure

Contributor-Level 10

Data is not sufficient but official answer is (D)

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8 months ago

4.0 moles of argon and 5.0 moles of PCl₅ are introduced into an evacuated flask of 100 litre capacity at 610 K. The system is allowed to equilibrate. At equilibrium, the total pressure of mixture was found to be 6.0 atm. The K_P for the reaction is

[Given R = 0.082 L atm K^-¹ mol^-¹]

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Contributor-Level 10

Moles of PCl₅ = 5 mol

Moles of Ar = 4 mol

Total no of moles = 9 moles

^{$P_{T o t a l} = \frac{n R T}{V} = \frac{9 * 0.0821 * 610}{100} = 4.5 a t m$}

^{$P_{P C l_{5}} = X_{P C l_{5}} * P_{T} = \frac{5}{9} * 4.5 = 2.5 a t m$}

^{$P_{A r} = X_{A r} * P_{T} = \frac{4}{9} * 4.5 = 2 a t m$}

$P C l_{5} \overset{}{?} P C l_{3} + C l_{2}$

2.5 00

2.5 PPP

$P_{T o t a l} = 2.5 - P + P + P + P_{A r} = 6$

P = 1.5 atm

$K_{P} = \frac{1.5 * 1.5}{1} = 2.25$

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8 months ago

Consider the species CH4, $N H_{4}^{+} a n d B H_{4}^{-} .$ $_{}^{}_{}^{}$ Choose the correct option with respect to the there species

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Contributor-Level 10

Species =CH4 $_{}^{}$ $N H_{4}^{+}$ $B H_{4}^{?}$ $_{}^{}$

Electrons =101010

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8 months ago

Which of the following is the correct plot for the probability density $ψ^{2} (r)$ $^{}$ as a function of distance 'r' of the electron from the nucleus for 2s orbital?

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Contributor-Level 10

For 2S, number of radial moles = $n - l - 1 = 2 - 0 - 1 = 1$ and $^{}$ $Ψ^{2} (r)$ will always be positive

$∴ o p t i o n (B) i s c o r r e c t ?$ it has one radial node and it is positive.

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8 months ago

Using the rules for significant figures, the correct answer for the expression $\frac{0.02858 * 0.112}{0.5702}$ $\frac{}{}$ will be

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What is pascal triangle in binomial theorem in class 11 maths?

Contributor-Level 10

$\frac{0.02858 * 0.112}{0.5702} = 0.0561$

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8 months ago

Class 11th Class 11

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SAMBIT GUMANSINGH

Contributor-Level 6

Pascal's Triangle is a triangular array of binomial coefficients where each number is the sum of the two numbers directly above it, and its rows provide the coefficients for binomial expansions according to the Binomial Theorem. This le man language for defition of the passcl triangle.

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8 months ago

The integral $\frac{24}{π} \int_{0}^{\sqrt[]{2}} \frac{(2 - x^{2}) d x}{(2 + x^{2}) \sqrt[]{4 + x^{4}}}$ $\frac{}{}_{} \frac{^{}}{^{}^{}}$ is equal to……………

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Contributor-Level 10

$\frac{24}{π} \int_{0}^{\sqrt[]{2}} \frac{(2 - x^{2})}{(x^{2} + 2) \sqrt[]{4 + x^{4}}} d x$

$\frac{24}{π} \int_{0}^{\sqrt[]{2}} \frac{x^{2} (\frac{2}{x^{2}} - 1) d x}{x (x + \frac{2}{x}) * x \sqrt[]{\frac{4}{x^{2}} + x^{2}}}$

$x + \frac{2}{x} = t$

$d t = (1 - \frac{2}{x^{2}}) d x$

$= - \frac{12}{π} [\frac{π}{4} - \frac{2 π}{2 * 2}] = - \frac{12}{π} [- \frac{π}{4}] = 3$

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8 months ago

If a₁ (> 0), a₂, a₃, a₄, a₅, are in G.P., a₂ + a₄ = 2a₃ + 1 and 3a₂ + a₃ = 2a₄, then a₂ + a₄ + 2a₅ is equal to…….

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Contributor-Level 10

$L e t G . P . b e a_{1} = a, a_{2} = a r, a_{3} = a r^{2}$ $_{}_{}_{}^{}$ , ….

$? 3 a_{2} + a_{3} = 2 a_{4}$

^{$\Rightarrow 3 a r + a r^{2} = 2 a r^{3}$}

$\Rightarrow 2 a r^{2} - r - 3 = 0$

$∴ a_{2} + a_{4} + 2 a_{5} = a (r + r^{3} + 2 r^{4})$

$= \frac{8}{3} (\frac{3}{2} + \frac{27}{8} + \frac{81}{8})$ = 40

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8 months ago

If and n are coprime, then m + n is equal to………

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Contributor-Level 10

Kindly consider the following figure

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8 months ago

The total number of 3-digit numbers, whose greatest common divisor with 36 is 2, is……….

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