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Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: options (i) and (iv)

Ice and water are in equilibrium only at particular temperature and pressure. For any pure substance at atmospheric pressure, the temperature at which the solid and liquid phases are at equilibrium is called the normal melting point or normal freezing point of the substance. For example, it is 4°C in case of water. The system here is in dynamic equilibrium.

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

The compound is water which undergoes self ionization.

The autoprotolysis (self-ionization) of water takes place as follows:

H2O (l)     +      H2O (l)             →        H3O+ (aq)         +          OH- (aq)

Acid                Base             &nb

...more

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans:, option (i), (iii) and (iv)

As, K increases with increase in temperature. K increases, it shows that the reaction must be endothermic. No. of molecules increases thus, there is increase in entropy.

New answer posted

5 months ago

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

Because of hydrogen bonding HF is liquid whereas HCl is gas as there is lack of hydrogen bonding in HCl.

New answer posted

5 months ago

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Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: option (iv) 

Since in all the given reaction, the volume is to be kept constant and an inert gas argon is added which will do not take part in reaction. So, the equilibrium will remain unaffected in all the given cases.

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5 months ago

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

Dihydrogen reacts with dioxygen to form water. The reaction is highly exothermic.

H2 (g) + O2 (g) → H2O (l)

? H = -285.9KJmol-1

The isotope of hydrogen which has one proton and one neutron is deuterium. When it reacts with O2 it forms Deuterium oxide (D2O). Deuterium reacts in a similar way but the reactivity will be lesser than hydrogen because of high bond dissociation enthalpy of D2 as compared to hydrogen.

New answer posted

5 months ago

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Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: option (i) 

If the equation is multiplied by 2, the equilibrium constant for the new equation is the square of K it means we must do the square of 5 that is 25. Then and on reversing the reaction the value of the equilibrium constant is inversed means the value of K comes out to be 1/25= 0.04. 

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5 months ago

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

D2O has greater intermolecular force of attraction. This is because D2O exhibits higher values for melting point, enthalpy of vaporization, and viscosity compared to H2O, indicating stronger intermolecular interactions needed to overcome these properties. 

New answer posted

5 months ago

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Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: option (ii)

 Greater the boiling point, lower will be the vapour pressure.

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5 months ago

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Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: Option(i)

The given reaction is :-

N2 (g) + 3H2 (g) ?2NH3 (g)

A/C to vart Hoff's eqn,

d l n K d T = ? M R T 2

K is dependent on temperature. As temperature remains constant at equilibrium, so K will remain constant in the given conditions.

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