Class 11th

Find out the oxidation number of chlorine in the following compounds and arrange them in increasing order of oxidation number of chlorine. NaClO₄ , NaClO₃ , NaClO, KClO₂ , Cl₂O₇ , ClO₃ , Cl₂O, NaCl, Cl₂ , ClO₂ . Which oxidation state is not present in any of the above compounds?

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Contributor-Level 10

This is a Long answer type question as classified in NCERT Exemplar

We can calculate the oxidation states by - ]

NaClO₄ Oxidation no. of chlorine = +7

Suppose oxidation number of chlorine is x then, 1 + x + 4 * (−2) = 0

∴ x - 7 = 0

x = +7

We can calculate, the oxidation states, as given below-

NaClO₃ Oxidation no. of chlorine = +5

? NaClO Oxidation no. of chlorine = +1

? KClO₂ Oxidation no. of chlorine = +3

? Cl₂O₇ Oxidation no. of chlorine = +7

ClO₃ Oxidation no. of chlorine = +6

Cl₂O Oxidation no. of chlorine = +1

NaCl Oxidation no. of chlor

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5 months ago

Write redox couples involved in the reactions (i) to (iv) given in question 2.

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This is a Long answer type question as classified in NCERT Exemplar

Redox couple are given as

Cu²⁺/Cu and Zn²⁺/Zn

Mg²⁺/Mg and Fe²⁺ /Fe

Br₂/Br^- and Cl₂ / Cl^-

Fe²⁺ /Fe and Cd²⁺/Cd

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5 months ago

Why does fluorine not show disproportionate reaction?

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Contributor-Level 10

This is a Long answer type question as classified in NCERT Exemplar

Disproportionate is defined as the reaction in which one compound of intermediate oxidation state converts to two compounds, one of higher and one of lower oxidation states So, to occur such type of redox reaction, the element should exist in at least three oxidation states. So that element present in the intermediate state and it can change to both higher and lower oxidation state during disproportionate reaction. Fluorine is the most electronegative element and a strong oxidizing agent and is the smallest in size of all the halogens. It does not show a positive oxidat

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5 months ago

On the basis of standard electrode potential values, suggest which of the following reactions would take place? (Consult the book for E V value).

(i) Cu + Zn²⁺ → Cu²⁺ + Zn

(ii) Mg + Fe²⁺ → Mg²⁺ + Fe

(iii) Br2 + 2Cl^– → Cl₂ + 2Br^–

(iv) Fe + Cd²⁺ → Cd + Fe²⁺

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Contributor-Level 10

This is a Long answer type question as classified in NCERT Exemplar

On the basis of standard reduction potential suggested in the reactivity series (ii) reaction can take place as Mg has more negative value of E? cell. Hence, Mg will be oxidized by losing electron and iron will be reduced by gaining electron.

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5 months ago

Explain redox reactions on the basis of electron transfer. Give suitable examples.

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Contributor-Level 10

This is a Long answer type question as classified in NCERT Exemplar

The given reaction is a redox change.

2Na (s)+H₂ (g)→2NaH (s)

The half reaction is:

2Na (s)→2Na⁺ (g)+2e^-

The other half reaction is:

H₂ (g)+2e^-→2H^- (g)

This splitting of the reaction into two half-reactions automatically reveals here that sodium is oxidized, and hydrogen is reduced. Any substance which loses electron is oxidized and gains electron is reduced hence is the case of sodium and hydrogen atoms respectively. Hence, the complete reaction is a redox change.

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5 months ago

Two balls of same mass and carrying equal charge are hung by threads of length $l$ from a fixed support. At electrostatic equilibrium, assuming that angles made by each thread is small, the separation, $x$ between the balls is proportional to:

(a.) $l$

(b.) $l^{2}$

(c.) $l^{2 / 3}$

(d.) $l^{1 / 3}$

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Contributor-Level 10

mg In equilibrium, $F_{} = θ$

$= θ$

$θ = \frac{F_{}}{} = \frac{^{2}}{4 π \in_{0}^{2} *}$

also $θ \approx ? = \frac{/ 2}{l}$

Hence, $\frac{}{2 l} = \frac{^{2}}{4 π \in_{0}^{2} *}$

$\Rightarrow^{3} = \frac{2^{2} p}{4 π ε_{0}}$

$= {(\frac{^{2} l}{2 π \in_{0}})}^{1 / 3}$

Therefore $\propto l^{1 / 3}$

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5 months ago

Based on the passage, which of the following best captures the meaning of HIF, or hypoxia-inducible factor?

A. It is a protein that increases inside the cell when the oxygen levels fall, helping the cell survive.
B. It inhibits oxygen carrying process in the body as the oxygen level increases inside the cell.
C. It enables cells to adapt quickly to the changing environment and helps in its survival.
D. It regulates the amount of oxygen available to the cell and the body during exercise.

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5 months ago

Based on the passage, which of the following best captures the meaning of HIF, or hypoxia-inducible factor?

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New answer posted

5 months ago

Based on the passage, which of the following best captures the meaning of HIF, or hypoxia-inducible factor?

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