Class 11th

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10 months ago

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Payal Gupta

Contributor-Level 10

29. (i) {1,2,3,4} ∩ {x : x is a natural number and 4 ≤ x ≤ 6}

{1, 2, 3, 4} ∩ {4, 5, 6}

{4} ≠∅

Hence, the given pair of set is not disjoint.

(ii) {a, e, i, o, u} ∩ {c, d, e, f}

{e} ≠∅

Hence, the given pair of set is not disjoint.

(iii) {x: x is an even integer} ∩ {x: x is are odd integer}.

=∅

As there is no integer which is both even and odd at the same time.

? Given pair of set are disjoint.

New answer posted

10 months ago

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P
Payal Gupta

Contributor-Level 10

28. A = {1,2,3,4,5, 6, …}

B = {2,4,6, …}

C = {1,3,5, …}

D = {2,3,5, …, }

(i) A ∩ B = {1,2,3,4 …} ∩ {2,4,6, …} = {2,4,6 …} = B.

(ii) A ∩ C = {1,2,3,4, …} ∩ {1,3,5 …} = {1,3,5, …} = C.

(iii) B ∩ C = {2,4,6, …} ∩ {1,3,5, …} = ?  .

(iv) B ∩ D = {2,4,6 …} ∩ {2,3,5 …} = {2}

(v) C ∩ D = {1,3,5, …} ∩ {2,3,5 …} = {3,5,7 …} = {x : x is odd prime number}

New answer posted

10 months ago

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Payal Gupta

Contributor-Level 10

27. (i) A ∩ B = {3,5,7,9,11} ∩ {7,9,11,13}

= {7, 9, 11}

(ii) B ∩ C = {7,9,11,13} ∩ {11,13,15}

= {11,13}

(iii) A ∩ C ∩ D = (A ∩ C) ∩ D

= [ {3,5,7,9,11} ∩ {11,13,15}] ∩ {15,17}.

= {11} ∩ {15,17} = ?  .

(iv) A ∩ C = {3,5,7,9,11} ∩ {11,13,15}.

= {11}

(v) B ∩ D = {7,9,11,13} ∩ {15,17}= ?

(vi) A ∩ (B∪ C) = {3,5,7,9,11} ∩ [ {7,9,11,13}∪ {11,13,15}]

= {3,5,7,9,11} ∩ {7,9,11,13,15}.

= {7,9,11}

(vii) A ∩ D = {3,5,7,9,11} ∩ {15,17} = ?  .

(viii) A ∩ (B ∪ D) = {3,5,7,9,11} ∩ [ {7,9,11,13} ∪ {15,17}]

= {3,5,7,9,11} ∩ {7,9,11,13,15,17}

= {7,9,11}

(ix) (A ∩ B) ∩ (B ∪ C) = [ {3

...more

New answer posted

10 months ago

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P
Payal Gupta

Contributor-Level 10

26. (i) X ∩ Y = {1,3,5} ∩ {1,2,3} = {1,3}

(ii) A = {a, e, i, o, u} ∩ {a, b, c} = {a}

(iii) A ∩ B = {3,6,9,12 …} ∩ {1,2,3,4,5}

= {3}

(iv) A ∩ B = {2,3,4,5,6} ∩ {7,8,9} = ?

(v) A ∩ B = {1,2,3} ∩ ? = ?

New answer posted

10 months ago

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Payal Gupta

Contributor-Level 10

25. (i) A B = {1, 2, 3, 4} {3, 4, 5, 6}

= {1, 2, 3, 4, 5, 6}

(ii) A C = {1, 2, 3, 4} {5, 6, 7, 8}

= {1, 2, 3, 4, 5, 6, 7, 8}

(iii) B C = {3, 4, 5, 6} {5, 6, 7, 8}

= {3, 4, 5, 6, 7, 8}

(iv) B D = {3, 4, 5, 6} {7, 8, 9, 10}

= {3, 4, 5, 6, 7, 8, 9, 10}

(v) A B C = (A B) C = {1,2,3,4,5,6} {5,6,7,8}

= {1, 2, 3, 4, 5, 6, 7, 8}

(vi) A B D = (A B) D = {1,2,3,4,5,6} {7,8,9,10}

= {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

(vii) B C D = (B C) D = {3,4,5,6,7,8} {7,8,9,10}

= {3, 4, 5, 6, 7, 8, 9, 10}

New answer posted

10 months ago

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Payal Gupta

Contributor-Level 10

24.If A? B then let a  A and also a  B.

but b  B and b  A i.e, A = {a} and B = {a, b}

So, A B = {x : x  A or x  B}

= {a, b}

= B

New answer posted

10 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

23. Given, A = {a, b}

B = {a, b, c}

Yes A  B as a, b  A and a, b  B.

And A B = {a, b} {a, b, c} = {a, b, c} = B

New answer posted

10 months ago

0 Follower 9 Views

P
Payal Gupta

Contributor-Level 10

22. (i) X∪ Y = {1,3,5}∪ {1,2,3} = {1,2,3,5}.

(ii) A ∪B = {a, e, i, o, u} ∪ {a, b, c} = {a, b, c, e, i, o, u}

(iii) A = {3, 6, 9, 12 …}

B = {1, 2, 3, 4, 5}

So, A∪ B = {3, 6, 9, 12, …}∪ {1, 2, 3, 4, 5}

= {1, 2, 3, 4, 5, 6, 9, 12 …}

(iv) A = {2, 3, 4, 5, 6}

B = {7, 8, 9}

So, A∪ B = {2, 3, 4, 5, 6}∪ {7, 8, 9} = {2, 3, 4, 5, 6, 7, 8, 9}

(v) A ∪B = {1, 2, 3} ∪?  = {1, 2, 3}.

New answer posted

10 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

21. Universal set of A, B and C must includes all elements of A, B and C, i.e. 0,1,2,3,4,5,6,8.

So, the universal set of A, B and C is (iii) {0,1,2,3,4,5,6,7,8,9,10}.

New answer posted

10 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

20. (i) The set of all triangles. U= {x : x is a triangle in a plane}

(ii) The set of all triangles. U= {x : x is a triangle in a plane}

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