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New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

The ozonolysis of 4-Ethylhex-3-ene gives propanal and pentan-3-one.
The structural formula of the alkene (4-Ethylhex-3-ene) is as shown.

(i) Write the structures of propanal and pentan-3-ene with their oxygen atoms facing each other, we have,
 
(ii) Remove oxygen atoms and join the two fragments by a double bond, the structure of the alkene is

New answer posted

a year ago

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Payal Gupta

Contributor-Level 10

3.39. In a period, the non-metallic character increases from left to right. Thus, among B, C, N and F, non-metallic character decreases in the order: F > N > C > B. However, within a group, non-metallic character decreases from top to bottom. Thus, C is more non-metallic than Si. Therefore, the correct sequence of decreasing non-metallic character is: F > N > C > B > Si, i.e., option (c) is correct.

New answer posted

a year ago

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Vishal Baghel

Contributor-Level 10

(i) An aldehyde with molar mass of 44 u is ethanal, CH3CH=0

(ii) Write two moles of ethanal side by side with their oxygen atoms pointing towards each other.

 
(iii) Remove the oxygen atoms and join them by a double bond, the structure of alkene 'A' is
As required, but-2-ene has three C—C, eight C—H a? bonds and one C—C? -bond.

New answer posted

a year ago

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P
Payal Gupta

Contributor-Level 10

3.38. In a period, metallic character decreases as we move from left to right. Therefore, metallic character of K, Mg and Al decreases in the order: K > Mg > Al. However, within a group, the metallic character, increases from top to bottom. Thus, Al is more metallic than B. Therefore, the correct sequence of decreasing metallic character is: K > Mg > Al > B, i.e., option (d) is correct

New answer posted

a year ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

Step 1. Write the structure of the products side by side with their oxygen atoms pointing towards each other.

Step 2. Remove the oxygen atoms and join the two ends by a double bond, the structure of the alkene 'A' is

New question posted

a year ago

0 Follower 8 Views

New answer posted

a year ago

0 Follower 11 Views

P
Payal Gupta

Contributor-Level 10

3.37.  (d) is incorrect.

New answer posted

a year ago

0 Follower 15 Views

V
Vishal Baghel

Contributor-Level 10

(a) Isomers of C4H8 having one double bond are:

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

(a) 2-Methykbuut-2-ene

(b) Pent-1-ene-3-yne

(c) But-1,3-diene

(d) 4-Phenylbut-1-ene

(e) 2-Methyl phenol (f) 5- (2-Methylpropyl)decane

(g) 4-Ethyldeca-1,5,8-triene

New answer posted

a year ago

0 Follower 30 Views

V
Vishal Baghel

Contributor-Level 10

Chlorination of methane is a free radical reaction which occurs by the following mechanism involving initiation, propagation and termination steps:

From the above mechanism, it is evident that during the propagation step, CH3 free radicals are produced, which may undergo three reactions, i.e., (i), (ii) and (iii). In the chain termination step, the two CH3 free radicals combine to form ethane (CH3—CH3) molecule.

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