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11 months ago

Class 11th Classification of Elements and Periodicity in Prop

3.39. Considering the elements B, C, N, F and Si, the correct order of their non-metallic character is:

(a) B>C>Si>N>F

(b) Si>C>B>N>F

(c) F>N>C>B>Si

(d) F>N>C>Si>B
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Payal Gupta

Contributor-Level 10

3.39. In a period, the non-metallic character increases from left to right. Thus, among B, C, N and F, non-metallic character decreases in the order: F > N > C > B. However, within a group, non-metallic character decreases from top to bottom. Thus, C is more non-metallic than Si. Therefore, the correct sequence of decreasing non-metallic character is: F > N > C > B > Si, i.e., option (c) is correct.

New answer posted

11 months ago

Class 11th Hydrocarbons

13.6. An alkene 'A' contains three C – C, eight C – H σ bonds and one C – C π bond. 'A' on ozonolysis gives two moles of an aldehyde of molar mass 44 u. Write IUPAC name of 'A'.
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Vishal Baghel

Contributor-Level 10

(i) An aldehyde with molar mass of 44 u is ethanal, CH3CH=0

(ii) Write two moles of ethanal side by side with their oxygen atoms pointing towards each other.

 
(iii) Remove the oxygen atoms and join them by a double bond, the structure of alkene 'A' is
As required, but-2-ene has three C—C, eight C—H a? bonds and one C—C? -bond.

New answer posted

11 months ago

Class 11th Classification of Elements and Periodicity in Prop

3.38. Considering the elements B, Al, Mg and K, the correct order of their metallic character is:

(a) B>Al>Mg>K

(b) Al>Mg>B>K

(c) Mg>Al>K>B

(d) K>Mg>Al>B
0 Follower 19 Views

P
Payal Gupta

Contributor-Level 10

3.38. In a period, metallic character decreases as we move from left to right. Therefore, metallic character of K, Mg and Al decreases in the order: K > Mg > Al. However, within a group, the metallic character, increases from top to bottom. Thus, Al is more metallic than B. Therefore, the correct sequence of decreasing metallic character is: K > Mg > Al > B, i.e., option (d) is correct

New answer posted

11 months ago

Class 11th Hydrocarbons

13.5. An alkene 'A' on ozonolysis gives a mixture of ethanal and pentan-3-one. Write structure and IUPAC name of 'A'.
0 Follower 4 Views

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Vishal Baghel

Contributor-Level 10

Step 1. Write the structure of the products side by side with their oxygen atoms pointing towards each other.

Step 2. Remove the oxygen atoms and join the two ends by a double bond, the structure of the alkene 'A' is

New question posted

11 months ago

Class 11th Hydrocarbons

13.4. Write IUPAC names of the products obtained by the ozonolysis of the following compounds:
(i) Pent-2-ene (ii) 3, 4-Dimethylhept-3-ene (iii) 2-Ethylbut-l-ene (iv) 1-Phenylbut-l-ene.
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New answer posted

11 months ago

Class 11th Classification of Elements and Periodicity in Prop

3.37. Which of the following statements is incorrect in relation to ionization enthalpy?

(a) Ionization enthalpy increases for each successive electron.

(b) The greatest increase in ionization enthalpy is experienced on removal of electrons from core noble gas configuration.

(c) End of valence electrons is marked by a big jump in ionization enthalpy.

(d) Removal of electron from orbitals bearing lower n value is easier than from orbital having higher n value.
0 Follower 11 Views

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Payal Gupta

Contributor-Level 10

3.37.  (d) is incorrect.

New answer posted

11 months ago

Class 11th Hydrocarbons

13.3. For the following compounds, write structural formulas and IUPAC names for all possible isomers having the number of double or triple bond as indicated:
(a) C4H8 (one double bond) (b) C5H8 (one triple bond)
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Vishal Baghel

Contributor-Level 10

(a) Isomers of C4H8 having one double bond are:

New answer posted

11 months ago

Class 11th Hydrocarbons

13.2. Write IUPAC names of the following compounds:

0 Follower 10 Views

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Vishal Baghel

Contributor-Level 10

(a) 2-Methykbuut-2-ene

(b) Pent-1-ene-3-yne

(c) But-1,3-diene

(d) 4-Phenylbut-1-ene

(e) 2-Methyl phenol (f) 5- (2-Methylpropyl)decane

(g) 4-Ethyldeca-1,5,8-triene

New answer posted

11 months ago

Class 11th Hydrocarbons

13.1. How do you account for the formation of ethane during chlorination of methane?
0 Follower 24 Views

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Vishal Baghel

Contributor-Level 10

Chlorination of methane is a free radical reaction which occurs by the following mechanism involving initiation, propagation and termination steps:

From the above mechanism, it is evident that during the propagation step, CH3 free radicals are produced, which may undergo three reactions, i.e., (i), (ii) and (iii). In the chain termination step, the two CH3 free radicals combine to form ethane (CH3—CH3) molecule.

New answer posted

11 months ago

Class 11th Environmental chemistry

14.40. Define (a) eutrophication (b) pneumoconiosis (c) Photochemical smog (d) Classical smog
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Vishal Baghel

Contributor-Level 10

(a) Eutrophication: When the growth of algae increases in the surface of water, dissolved oxygen in water is reduced. This phenomenon is known as eutrophication. (Due to this growth of fish gets inhibited).

(b) Pneumoconiosis: It is a disease which irritates lungs. It causes scarring or fibrosis of the lung.

(c) Photochemical smog: Photochemical smog is formed as a result of the photochemical decomposition of nitrogen dioxide and chemical reactions involving hydrocarbons. It takes place during dry warm season in the presence of sunlight. It is oxidising in nature.           

(d) C

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